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Thread: Sum of Digits in Java

  1. #1
    Junior Member
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    Feb 2014
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    Default Sum of Digits in Java

    import java.util.Scanner;
    public class CubesSum {
        public static void main (String [] args){
            int input;
            System.out.println("Enter a positive integer:");
            Scanner in = new Scanner(System.in);
            input = in.nextInt();
            int number = input; //number is a temp variable
            int sum = 0;
                int t= number%10;
                sum += t*t*t;
                number = number/10;
            System.out.println("The sum of the cubes of the digits is:" +sum);

    As you can see I'm using a while loop. For part B which is to modify to determine what integers of two, three, and four digits are equal to the sum of the cubes of their digits. So for example, 371 = 3+7+1. Can someone tell me how to do it? I need to wrap a for loop around my while loop...

  2. #2
    Join Date
    Sep 2013
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    Thanked 7 Times in 7 Posts

    Default Re: Sum of Digits in Java

    So you are trying check a number is armstrong number or not.

    First you have to define a till which integer value you want to find out, and iterate you while loop inside a for/while loop.

  3. #3
    Super Moderator
    Join Date
    Jun 2013
    So. Maryland, USA
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    Thanked 697 Times in 679 Posts

    Default Re: Sum of Digits in Java

    Welcome to the forum! Thank you for taking the time to learn to post your code correctly.

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