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Method problem
Hi again
Ok so this time I was fiddling around with methods, and trying to figure them out, and once I got them working I got this error - illegal start of expression.
the error appears on the line which I spaced out, and I was wondering what the problem is. When I go shift-F6, the file runs fine, however I want to know what the error is.
thanks,
Skeptile
Related threads:
Re: Method problem
Your squiggly braces are in disarray... always keep them nice and lined up so you can see where everything ends and begins. Something is wrong with your braces. They should look like this and your app will run fine.
public class InClass
{
public static void main(String[] args)
{
method1();
method2();
}
public static void method1()
{
System.out.println( "hello" );
}
public static void method2()
{
System.out.println( "hello" );
}
}
--- Update ---
I believe your methods are inside of your main method because of the way your squiggly braces are set up. You should never have methods in your main method. That's why you're getting a compile error.
skeptile2 (March 6th, 2013)
Re: Method problem
You are not allowed to define a method within another method. Separate your method definitions out of your main method.
Things you should know about Methods:
Method:
-A method is invoked by a method call - Name(args)
-Most methods are invoked through a reference call to a object
-Method args can be: variables, constants, expressions
-Must be defined in a class definition
-Format: return-type method-name(paramter list){declarations and statements}
-At most can return 1 value
-A method cannot be defined inside another method.
-Method control is given back to caller when } is reached or return;
Variables:
-Variables in method definitions are local to that method only
-Instance variables should be only used if they are required in more than
one method.
Method Calls:
-thisMethod();
-object.method(); //object refers to class
-Class.method(); //static methods
Re: Method problem
you call the method like this in main method...Originally Posted by skeptile2
methodTest1a m; m = new methodTest1a(); m.Method1(); m.Method2();
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