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Thread: Logic of Hangman

  1. #1
    Junior Member
    Join Date
    Mar 2013
    Thanked 0 Times in 0 Posts

    Default Logic of Hangman

    I'm working on a project for school and was curious
    whether there is a better way to perform some the
    logic in my hangman program. It plays like hangman
    but you can't lose depending on the number of moves.

    import java.util.*;
    class Hangman {
        static Scanner scan = new Scanner(System.in);
        static Random rand = new Random();
        static boolean isIn(char c, String str) {
            int occurrence = str.indexOf(c);
            if (occurrence >= 0)
                return true;
                return false;
        static boolean printCurrStatus(String strToGuess, String userInputs) {
            String current = "";
            String positionTemp = "";
            String currentTemp = "";
            for (int i = 0; i < strToGuess.length(); i++) {
                current += "_" + " ";
                positionTemp += strToGuess.charAt(i) + " ";
            for (int i = 0; i < userInputs.length(); i++) {
                char input = userInputs.charAt(i);
                if (isIn(input, strToGuess)) {
                    int index = 0;
                    int position = 0;
                    while (index > -1) {
                        index = positionTemp.indexOf(input, position);
                        if (index < 0)
                        else {
                            currentTemp = current.substring(0, index) + input;
                            currentTemp += current.substring(index + 1,
                                    positionTemp.length() - 1);
                            current = currentTemp;
                            position += 1;
            if (current.indexOf('_') < 0)
                return true;
                return false;
        static String getNextWordToGuess() {
            String[] nextWord = { "elephant", "tiger", "monkey", "baboon",
                    "barbeque", "giraffe", "simple", "zebra", "porcupine",
                    "aardvark" };
            int newRandom = rand.nextInt(nextWord.length);
            return nextWord[newRandom];
        static void playGame() {
            String userInput = "";
            String wordToGuess = getNextWordToGuess();
            while (!printCurrStatus(wordToGuess, userInput))
                System.out.println("Enter next letter:");
                userInput += scan.next();
        public static void main(String[] args) {
            String choice = "y";
            while (choice.equals("y")) {
                System.out.println("Do you want to play again?  (y or n)");
                choice = scan.next();
            System.out.println("Thanks for playing!");

    Everything works fine but I'm curious on whether there
    is a way to simplify the printCurrStatus method. I do not
    want to change this method into multiple methods.

    I'm new to the site and appreciate your time. I hope to
    be a contributor soon.

  2. #2
    Super Moderator Norm's Avatar
    Join Date
    May 2010
    Eastern Florida
    Thanked 2,465 Times in 2,416 Posts

    Default Re: Logic of Hangman

    Hard to tell. The comments in the code don't say anything about the program's logic.
    If you don't understand my answer, don't ignore it, ask a question.

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