scope of a class created as local variable

**Samaras** · August 25th, 2012, 08:40 AM

My question is.Will the temp variable will be set to null,so it is going to be de-allocated after the termination of the function?
NothingHere is a class.voidPositionList is a list.

private final void initVoidPositions() {
        NothingHere temp = new NothingHere("Road");
        voidPositionList.add(temp);
    }

**Norm** · August 25th, 2012, 08:54 AM

The variable: temp will disappear when the method exits.
The object that temp refers to has a reference saved in the list and will continue to exist and be accessible.

**Samaras** · August 25th, 2012, 09:50 AM

Thank you very much.If no reference exists to the object,then it is going to be removed by garbage collector.

**Norm** · August 25th, 2012, 09:53 AM

Yes, that's how its supposed to work.

**Samaras** · August 25th, 2012, 04:54 PM

Thank you very much for you laconic answers.

**pbrockway2** · August 25th, 2012, 05:22 PM

Originally Posted by Samaras

Thank you very much.If no reference exists to the object,then it is going to be removed by garbage collector.

Norm (#4) is right. But I don't think any promise is made about when memory will be freed. Or whether it will be freed this side of your program's termination.

The point is that a reference to the object does exist as one of the things in the list, so the newly created NothingHere instance is quite "safe".

**Samaras** · August 25th, 2012, 06:01 PM

Originally Posted by pbrockway2

Norm (#4) is right. But I don't think any promise is made about when memory will be freed. Or whether it will be freed this side of your program's termination.

Yes,i agree with you too

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