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Thread: 404 Status Error

  1. #1
    Junior Member
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    Aug 2012
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    Unhappy 404 Status Error

    web.xml file



    import java.io.*;
    import javax.servlet.ServletException;
    import javax.servlet.annotation.WebServlet;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;

    public class MyServlet extends HttpServlet {

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    PrintWriter out=response.getWriter();

    int x=Integer.parseInt(request.getParameter("n1"));
    int y=Integer.parseInt(request.getParameter("n2"));
    out.println("The addition of numbers is "+ (x+y));


    <h1>Mathematical Functions</h1>
    <form action="MyServlet" method="get">
    First number:<INPUT type="number" size="5" name="n1"><br>
    Second number:<INPUT type="number" size="5" name="n2">

    <input type="submit" value="Submit">

    I am getting the folllowing error .
    type Status report

    message /f/

    description The requested resource (/f/) is not available.

    f.war is the file i created.
    Everything like installing, jdk, apache tomcat is perfect as i have run other programs using the same process. Please help me in solving this error

  2. #2
    Junior Member
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    Default Re: 404 Status Error

    preeti91...if you don't have a default page and don't specify MyServlet in the URL then you will get a 404.

    Did you try .../f/MyServlet ?

  3. #3
    Think of me.... Mr.777's Avatar
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    Default Re: 404 Status Error

    First, to start from your login.html page, either you need to map it on your deployment descriptor(web.xml), then do HOST_NAMEORT and after that, in your login.html, put in the form tag, the action attribute which would actually request container for your servlet. If you still facing the problem, let us know.
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