Thread: prininting out a 4x4 array according to an order by a 1d array

Hi Guys,

I know i have posted quiyte a bit in the past couple of days and really greatful for all the help but i have hit a dead end again and been trying to figure it out for a few days now.

Right this is what i am trying to achive


I have a 2d array (blockarray[][]) which contains bytes of data and what i am trying to do is put each colomn into a String via a specic order which is set by the1d array (int[] colprintorder = new int[numberofcols]; ) which is the length of the 2d array containing the numbers 0-the number of coloumns in the array. This is the order i want each coloumn to be printed out (i know the order makes no sense its part of a transposition cipher thing).



So if you have a look at the photo above it may help you undfer stand what im trying to do . the black text is the byte array of the data, the orange array is the list i want each colom of the black array put into a single string. the green arrow is just demonstarating that im trying to print out the column and not row. So coloumn 8 (the one with the orange 0 above) will be printed out first then column 9 and so on till all the columns have been printed



you see the last 10 entrys are "21" i want these to be ignored so i tried creating a if between 32-177 (this range is beacuse it equals all usable characters on a english keyboard).


here is the code i have produced to try and do this

boolean end = false;
 
int mewo=0;
while(end==false)
{
    if(her==colprintorder.length)
    {
        end = true;
    }
 
 
    for (int posloop=0; posloop <colprintorder.length; posloop++)
    {
 
        if(colprintorder[posloop]==mewo)
        {
             for (int b=0; b<4;b++)
             {
 
 
                 cipherchararray[her] = (char)(byte) BlockArray[b][mewo];
 
             }
            her++;
        }
 
    }
 
 
}
 
String covertedChars = new String(cipherchararray);

at the moment im getting no where can anyone help me figure this out please .. thank you

i have used various combinations of whiul loops, ifs and fors but still not getting anywhere

right guys i have been playing around with tree mapping, i dont really know whats happening , ive got my code stuck im trying to add each coloumn to the 1d char array. Could you please steer me in the right direction. Thanks

String aaa ="";
 
TreeMap <Integer, Byte>tMap = new TreeMap<Integer, Byte>();
TreeMap <Integer, Byte>tMap1 = new TreeMap<Integer, Byte>();
TreeMap <Integer, Byte>tMap2 = new TreeMap<Integer, Byte>();
TreeMap <Integer, Byte>tMap3 = new TreeMap<Integer, Byte>();
 
 
 
Object heee;
String lolcat= null;
 
 
 
byte[] cipherf = new byte[4*numberofcols];
 
 
for(int i=0; i< colprintorder.length; i++)
{
tMap.put(colprintorder[i],BlockArray[0][i]);
tMap1.put(colprintorder[i],BlockArray[1][i]);
tMap2.put(colprintorder[i],BlockArray[2][i]);
tMap3.put(colprintorder[i],BlockArray[3][i]);
}
System.out.print("\n\n");
 
System.out.println("Values of tree map: " + tMap.values() );
System.out.println("Values of tree map: " + tMap1.values());
System.out.println("Values of tree map: " + tMap2.values());
System.out.println("Values of tree map: " + tMap3.values());
 
System.out.println("size: " +tMap.size());
 
 
 
 
  for(int a=0;a<tMap.size();a++)
  {
    cipherf[a] = tMap.get(a);  
 
    System.out.println("cipherf @" +a+" = "+ tMap.get(a)); 
 
  }
 
  for(int a=0;a<4;a++)
  {
    cipherf[a] += tMap.get(a);
    cipherf[a+1]= tMap1.get(a);
    cipherf[a+2] = tMap2.get(a);
    cipherf[a+3] = tMap3.get(a);
  }
 
for(int a=0; a<cipherf.length; a++)
{
    System.out.printf("%4s",cipherf[a]);
}

my output is:



You can see that the array at the bottom is now in order by the column print order.


i need to somehow deal with 1 treemap instead of 4 for each row I also need to put each of the 4 bits in each column into a 1d byte array from right to left (no certain order). For example in the testing output the data in the greenbox first then the orange box also would like to tidy the code up i am just messing around at the mo.

cheers and good night

Looks like you are on the right track. You could just have a single treemap specify the index in the array, and not necessarily the value at that index. So for example

Map<Integer, Integer> lookup = new TreeMap<Integer,Integer>();
for ( int i = 0; i < colprintorder.length; i++ ){
    lookup.put(colprintorder[i], i);
}
//now iterate over each row of block array, see code example below

As I mentioned above, you could also do this with just an array

int[] lookup = new int[colprintorder.length];
for ( int i = 0; i < colprintorder.length; i++ ){
    lookup[colprintorder[i]] = i;
}
//then like above, do the math to find the corresponding location in the blockarray...pseudocode
for each row:
    for each value in row:
        nextvalue = blockarray[rownumber * rowlength + lookup[colnumber]];

I can't guarantee the validity of the math of the above pseudo-code, but hopefully its enough to get you pointed in the right direction.

i think the best way is to use treemaps because it orders them ect how i need the array i just need to find a way which i dont need 4 serpearte treemaps for each row and a way to convert the treemap to an array which i can print out each coloum in a string (greenbox then orange box and so on