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Thread: Direction,

  1. #1
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    Default [SOLVED] Direction,

    Ok, here's the idea.

    Point A is a random location,

    It wants to travel to point b an adjacent point, I need a method to return the direction of the prime point A, in perspective to point b,

    i.e if a point is at, 0,0 and A point (adjacent) Is at point 1,1, The method return north-east (String),

    For a closer look here: (Sorry for poor artistic abilitys,)



    The main Point A = at 0,0 (Lavander)

    The adjacent point b is at 1,1 (Lightblue),

    The method should return that the relationship shared between the points is Northwest,

    Keep these in mind:
    -Point A is the main point so relationships stem from there,
    -The directions are North, Northeast, Northwest, South, Southeast, Southwest, East, West,
    Thanks for reading, I hope someone come's up with a method =P

    -Time,
    Last edited by Time; May 21st, 2010 at 05:21 PM.


  2. #2
    Super Moderator helloworld922's Avatar
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    Default Re: Direction,

    pseudo-code:

    1. create a vector from point A to B (just subtract their coordinates)
    2. Get the angle from the positive X axis (or any axis you want, this is easiest because there's a built in function to do this)
    3. Use if/else statements to see which quadrant it's in, and return the appropriate response
    in degrees (assuming all angles are measured counter-clockwise from the positive X-axis):
    angle == 0: east
    0 > angle < 90: north-east
    angle == 90: north
    90 > angle < 180: north-west
    angle == 180: west
    180 > angle < 270: south-west
    angle == 270: south
    270 > angle < 360: south-east

  3. #3
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    Default Re: Direction,

    Quote Originally Posted by helloworld922 View Post
    pseudo-code:

    1. create a vector from point A to B (just subtract their coordinates)
    2. Get the angle from the positive X axis (or any axis you want, this is easiest because there's a built in function to do this)
    3. Use if/else statements to see which quadrant it's in, and return the appropriate response
    in degrees (assuming all angles are measured counter-clockwise from the positive X-axis):
    angle == 0: east
    0 > angle < 90: north-east
    angle == 90: north
    90 > angle < 180: north-west
    angle == 180: west
    180 > angle < 270: south-west
    angle == 270: south
    270 > angle < 360: south-east
    Thank's method created and it works like a charm.