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Thread: Array exception out of bounds

  1. #1
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    Exclamation Array exception out of bounds

    import java.util.Scanner;
    public class masyvai
    {
    public void masyvas()
    {
    //sk – 5 , z – 2,4,6,8
    Scanner scan2 = new Scanner(System.in);
    int a,b;
     
    System.out.printf("Iveskite eiluciu kieki");
    a=scan2.nextInt();
    System.out.printf("Iveskite stulpeliu kieki");
    b=scan2.nextInt();
    int mtr[][] = new int[a][b];
     
     
    System.out.println(" --------------------------------------------------");
    System.out.println("| Sumavimas | Atimtis |");
    System.out.println(" --------------------------------------------------");
     
    for (int eil = 0; eil < a; eil++)
    {
    for (int stul = 0; eil < b; stul++)
    {
     
    System.out.print(" "+mtr[eil][stul]); // error here, wtf???
    }
    System.out.print("\n");
     
    }
    scan2.close();
     
    }
    }

    What can be the problem here? I really dont understand, I used this code on my netbook (XP win) and it works fine but when i used it on my pc (win7) it crashes and gives me a gift:

    Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 2
    at masyvai.masyvas(masyvai.java:28)


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    Default Re: Array exception out of bounds

    Why are you comparing eil to both a and b in your inner and outer loop? Is that really what you want to be doing in your inner loop?
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    Default Re: Array exception out of bounds

    Hello gabberlt. Welcome to the Java Programming Forums.

    The java.lang.ArrayIndexOutOfBoundsException means that your Array Index is Out of Bounds

    I would look at the for loops. Try using System.out.println(); to see what's going on.
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