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Thread: Code working, but not the way I thought...

  1. #1
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    Default Code working, but not the way I thought...

    I've been playing around with some Java code (not my first language, but I'm trying to wrap my brain around it), but it is not giving me what I expected. I must not be looking at it correctly. I'd appreciate any suggestions on where I am mistaken..

    HTML Code:
    public class Mix5 {
    
       public static void main(String[] args) {
    		
         int x = 0;  //declare int named "x" & set value to 0
         int y = 30; //declare int named "y" & set value to 30
    		
       for(int outer = 0; outer < 3; outer++) { 
        //Outer for loop: declare int named "outer", set value to 0. 
         //while value is less than 3, increment by 1.
    			
          for(int inner = 4; inner > 1; inner--) { 
           //Inner for loop: declare int named "inner", set value to 0.
            //while is greater than 1, decrement by 1.
    				
    	y = y - 2; //y = value of y (30) - 2 (28)
    				
             if(x == 6) { 
                  break;
             } //when x equals 6, break out of loop.
    				
            x = x + 3; //x = value of x(0) + 3 (3)
    	 } //end inner for loop.
    
    	y = y - 2; //y = value of y (28) - 2 (26)
    	 } //end outer for loop.
    
    	System.out.println(x + " " + y); //Print out value of x and y.
    	 } //end main Method.
    } //end Class.
    Here's how I would THINK it would behave:

    Setup:
    x is set to 0 and y is set to 30.
    In outer loop, int outer set to 0, and incremented by 1 until it = 3.
    In inner loop, int inner set to 4, and decremented by 1 until it = 1.
    Both loops should then complete a total of 3 times.

    Action (Loop 1):
    y equals itself (30) - 2 = 28.
    a check is made, if x equals 6 (it doesn't yet), then break.
    x equals itself (0) + 3 = 3.
    y equals itself (now 28) - 2 = 26

    Action (Loop 2):
    y equals itself (26) - 2 = 24.
    a check is made, if x equals 6 (it doesn't yet), then break.
    x equals itself (3) + 3 = 6.
    y equals itself (now 24) - 2 = 22

    Action (Loop 3):
    y equals itself (now 22) - 2 = 20
    a check is made, if x equals 6 (it now does), then break.
    Break out of loops.
    Print a line with the value of x and the value of y. It should be:

    6 20

    However, what I get when I run this is:

    6 14

    Does my if statement only break me out of the inner for loop, not both? This is the only reason I can think that it would continue to process.


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    Default Re: Code working, but not the way I thought...

    Quote Originally Posted by JLogan3o13 View Post
    Does my if statement only break me out of the inner for loop, not both? This is the only reason I can think that it would continue to process.
    Bingo. Use a debugger, or at least put in some print statements, to make sure of that.

    The most obvious way to fix this would be to look into labeled statements.

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