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Thread: Die Rolling - Continuing the statement?

  1. #1
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    Default Die Rolling - Continuing the statement?

    What's up all,

    I have a second problem. This one I've come close to. The point is to make a die-rollng game that the user can choose to terminate, or continue. I've pretty much written it all, except I'm stuck at one point:

    System.out.println("Craps!");
    else {
    System.out.println("Do you want to roll again? (1 = yes, 2 = no): ");
    accept = input.nextInt();

    That part. What I want is for the user to be able to once again, enter 1 or 2 to continue the program or terminate it. However, it doesn't do this. How can I make it so that it does. I assumed that if the user enters one, the first "if" statement will execute again, but it's not. What am I doing wrong?

    Thanks guys. Here is the code:






     
    package dieroll;
    import java.util.Scanner;
    public class Main {
    public static void main(String[] args) {
     
          System.out.println("Welcome to Anthony's Die Roll application!");
     
         int die1 = (int)(Math.random() * 6);
         int die2 = (int)(Math.random() * 6);
         int i;
     
         if (die1 == 0 || die2 == 0)
             die1 = (die1 + 1);
             die2 = (die2 + 1);
     
         Scanner input = new Scanner(System.in);
         System.out.print("Do you want to roll the die? (1 = yes, 2 = no): ");
         int accept = input.nextInt();
     
     if (accept == 1){
             System.out.println(die1 + " " + die2);
           if (die1 == 1 && die2 == 1)
              System.out.println("Snake eyes!");
            else if (die1 == 6 && die2 == 6)
              System.out.println("Box cars!");
            else if (die1 == 2 && die2 == 5)
              System.out.println("Craps!");
           else {
              System.out.println("Do you want to roll again? (1 = yes, 2 = no): ");
              accept = input.nextInt();
     
                  }
                         }
     else {
         System.out.println("Thanks for playing!");
         System.exit(0);
           }
     
    }
     
    }
    Last edited by Override; October 29th, 2010 at 12:33 AM.


  2. #2
    Member Darryl.Burke's Avatar
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  3. #3
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    Default Re: Die Rolling - Continuing the statement?

    Are my loops for the different results completely wrong?

  4. #4
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    Default Re: Die Rolling - Continuing the statement?

    Okay, I fixed it. My only problem is that the number on the die don't change each time it is re-executed. The "Roll" changes, but that's about it. Any suggestions?

     
    package dieroll;
    import java.util.Scanner;
    public class Main {
    public static void main(String[] args) {
     
          System.out.println("Welcome to Anthony's Die Roll application!");
     
         int i;
         int number_of_plays = 1;
     
     
         Scanner input = new Scanner(System.in);
         System.out.print("Do you want to roll the die? (1 = yes, 2 = no): ");
         int accept = input.nextInt();
     
     
     while (accept == 1) {
     
          int die1 = (int)(Math.random() * 6);
          int die2 = (int)(Math.random() * 6);
     
             if (die1 == 0 || die2 == 0)
             die1 = (die1 + 1);
             die2 = (die2 + 1);
     
          for (i = 1; i < 1000; i++){
          number_of_plays = i;
     
         System.out.println("Roll " + number_of_plays + ":" + " " + die1 + " " + die2);
     
              if (die1 == 1 && die2 == 1){
               System.out.println("Snake eyes!");
              if (die1 == 6 && die2 == 6);
               System.out.println("Box cars!");
              if (die1 == 2 && die2 == 5)
               System.out.println("Craps!"); }
     
              else
             System.out.println("Do you want to roll again? (1 = yes, 2 = no): ");
             accept = input.nextInt();
                         }
       while (accept != 1) {
         System.out.println("Thanks for playing!");
         System.exit(0);
           }
        }
        }
     
    }

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