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Thread: Printing the Max and Min in an Array

  1. #1
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    Default Printing the Max and Min in an Array

    Another one for you guys if you want to help me out... This program is supposed to print the maximum and minimum value in an array. It doesn't. There's a problem in my logic and I cannot figure it out! I've been staring at it too long.

    I'm new to Java, that's why all these are pretty simple to you gurus... thoughts?

    EDIT: I lied, I wanted first and second maximum numbers. Sorry :$

     class A3Q3b
    {
        public static void main (String[] args) 
        {  
         // DECLARE VARIABLES/DATA DICTIONARY 
         int [] a;           // GIVENS: the array of values
         int index;          // INTERMEDIATES: index through array
         int first, second;  // RESULTS: values of Max and Second Max
     
         System.out.println( "Please input the array:  " );
         a =  ITI1120.readIntLine();
     
          // BODY OF ALGORITHM
         first =  a[0]; second = a[0];
         index = 1; 
     
         while (index > a.length)
         { 
           if (a[index] < first)
           { 
              second = first;
              first = a[index];
           }
           else
           { 
             if (a[index] < second) 
             {
                second = a[index];
             }
     
           }
           index = index + 1;  
         }
     
         System.out.println("The maximum number is " + first);
         System.out.println("The second number is " + second);
      }
    }
    Last edited by bonbon242; October 29th, 2010 at 09:14 AM.


  2. #2
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    Default Re: Printing the Max and Min in an Array

    Are your <'s and >'s backwards? And probably easier to use a for loop to count through an array

    int min = a[0];
    int max = a[0];

    for(int i = 0;i<a.length;i++) {
    if(a[i]>max) max = a[i];
    if(a[i]<min) min = a[i];
    }

    if you wanted first and second highest, as it seems in the code, I would
    int min = a[0];
    int max = a[0];
    int second = a[0];

    for(int i = 0;i<a.length;i++) {
    if(a[i]>max){
    second = max;
    max = a[i];
    }
    if(a[i]<min) min = a[i];
    }

  3. The Following User Says Thank You to Zula For This Useful Post:

    bonbon242 (October 29th, 2010)

  4. #3
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    Default Re: Printing the Max and Min in an Array

    That did it. Thanks a lot

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