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Thread: Problem with the output

  1. #1
    Junior Member
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    May 2018
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    Unhappy Problem with the output

    Hey Guys! I have an issue here. This is my current exercise what I must complete but the but the output is not what I want. This is my first post btw and I wait your hints, tips and help. The problem is that my result println do not print Result 5 for the output but print Result 2. I try to change catch block and change nextInt(); methods and correct the if statement but canīt figure out what is the issue.
    I appreciate any help ! Thanks !

    import java.util.Scanner;
    import java.util.*;

    public class ExceptionInAddition {
    public static void main(String[] args) {
    Scanner reader = new Scanner(System.in);
    int firstNumber = 0, secondNumber = 0, result;
    boolean inputCorrect = true;

    do {
    try {
    System.out.println("Type in the first number: ");
    firstNumber = reader.nextInt();
    inputCorrect = true;
    } catch (java.util.InputMismatchException p) {
    inputCorrect = false;
    }
    } while (!inputCorrect);

    do {
    try {
    System.out.println("Type in the second number: ");
    reader.next();
    inputCorrect = true;
    } catch (java.util.InputMismatchException p) {
    inputCorrect = false;
    }
    } while (!inputCorrect || (secondNumber == 0));
    if (inputCorrect == true) {
    result = firstNumber + secondNumber;
    System.out.println("Result: " + result);
    } else {
    System.out.println("You did not type in an integer!");
    }
    }

  2. #2
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    Default Re: Problem with the output

    What input are you using? The reason I ask is because the way the code is now it will never print the result... unless i'm miss reading the question.

    The reason it will not print any result is because the variable "secondNumber" is never set. So it is always zero. That means it will not go past the while loop for the second number.

    As a separate issue, it might be a good idea to add the line "reader.nextLine();" after "inputCorrect = false;" for both instances. That will allow the Scanner to block while the user enters the input. There's a good explanation for this here: https://stackoverflow.com/a/13102066 Otherwise there will be some unexpected behavior after any invalid input.
    Last edited by User2009; May 16th, 2018 at 07:44 PM. Reason: elaboration of original response.

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