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Thread: Taylor series for e^x

  1. #1
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    Default Taylor series for e^x

    Hi I was bussy making some exercises for my exams and had to write a program to calculate Taylor series for e^x.
    Our prof lecturer gave us the solution but don't understand why he does it like this

    import java.util.Locale;
    import java.util.Scanner;

    public class TaylorReeks{
    // versie van het berekenen van een Tailorreeks waarbij de grootte van decimale getallen onder controle wordt gehouden.
    public static void main(String[] args){

    Scanner scanner = new Scanner(System.in).useLocale(Locale.US);
    System.out.println("Geef een getal x in : ");

    double x = scanner.nextDouble();
    double threshold = 0.1;

    int teller = 1;
    double component = x;

    double exponentVorig = 1.0;
    double exponentHuidig = 1 + x;

    while (Math.abs(exponentHuidig - exponentVorig) > threshold){
    teller = teller + 1;
    component = component * x / teller;
    exponentVorig = exponentHuidig;
    exponentHuidig = exponentVorig + component;

    }

    System.out.println("De waarde berekend met Math.E is: " + Math.pow(Math.E, x));
    System.out.println("De waarde berekend door het algoritme is: " + exponentHuidig + ".");
    System.out.println("Het aantal iteraties is:" + teller + ".");
    }
    }

  2. #2
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    Default Re: Taylor series for e^x

    why he does it like this
    Please ask some specific java programming questions about the lines of code you are having problems with.

    Please edit your post and wrap your code with code tags:

    [code]
    **YOUR CODE GOES HERE**
    [/code]

    to get highlighting and preserve formatting.
    If you don't understand my answer, don't ignore it, ask a question.

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