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Thread: problem in calling a method

  1. #1
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    Default problem in calling a method

    I need a Java API which to call an URL and process what it return for part b in . the programs are what i did for the part a and c.


    a. Enables the entry in a queue of a list of names of astronomical objects then to specify that the seizure is complete (by an empty string for example)
    b. The program reviews the names entered and verifies that they are recognized names by the name resolver Sesam:
    i. If yes we keep the name (or identifier) principal of the object. returns
    ii. Otherwise we do not do anything and we move on to the next.
    c. Finally, this program generates a text file (whose name can be entered) including all

    This is my java program for the first and last part
    Read a string from console using a BufferedReader.

    import java.io.*;

    class BRReadLines {
    public static void main(String args[]) throws IOException {
    // create a BufferedReader using System.in
    BufferedReader br = new BufferedReader(new
    InputStreamReader(System.in));
    String str;
    System.out.println("Enter lines of text.");
    System.out.println("Enter 'stop' to quit.");
    do {
    str = br.readLine();
    System.out.println(str);
    } while (!str.equals("stop"));
    }
    }

    And this one for the third part
    A tiny editor.

    <code>
    import java.io.*;
    class TinyEdit {
    public static void main(String args[]) throws IOException {
    // create a BufferedReader using System.in
    BufferedReader br = new BufferedReader(new
    InputStreamReader(System.in));
    String str[] = new String[100];
    System.out.println("Enter lines of text.");
    System.out.println("Enter 'stop' to quit.");
    for (int i = 0; i < 100; i++) {
    str[i] = br.readLine();
    if (str[i].equals("stop"))
    break;
    }
    System.out.println("\\nHere is your file:");
    // display the lines
    for (int i = 0; i < 100; i++) {
    if (str[i].equals("stop"))
    break;
    System.out.println(str[i]);
    }
    }
    }
    </code>


    Thanks

  2. #2
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    Default problem in calling a method

    I need a Java API which call an URL and process what it return (i want to verify that the names entered are recognized names in the URL the part b) . the programs are what i did for the part a and c.

    a. Enables the entry in a queue of a list of names of astronomical objects then to specify that the seizure is complete (by an empty string for example)
    b. The program reviews the names entered and verifies that they are recognized names by the name resolver Sesam:
    i. If yes we keep the name (or identifier) principal of the object. returns
    ii. Otherwise we do not do anything and we move on to the next.
    c. Finally, this program generates a text file (whose name can be entered) including all

    This is my java program for the first and last part
    Read a string from console using a BufferedReader.
        import java.io.*;
     
        class BRReadLines {
    	    public static void main(String args[]) throws IOException {
    		    // create a BufferedReader using System.in
    		    BufferedReader br = new BufferedReader(new 
        InputStreamReader(System.in));
    		    String str;
    		    System.out.println("Enter lines of text.");
    		    System.out.println("Enter 'stop' to quit.");
    		    do {
    			    str = br.readLine();
    			    System.out.println(str);
    		    } while (!str.equals("stop"));
    	    }
        }
    And this one for the third part
    A tiny editor.

        import java.io.*;
        class TinyEdit {
    	    public static void main(String args[]) throws IOException {
    		    // create a BufferedReader using System.in
    		    BufferedReader br = new BufferedReader(new 
        InputStreamReader(System.in));
    		    String str[] = new String[100];
    		    System.out.println("Enter lines of text.");
    		    System.out.println("Enter 'stop' to quit.");
    		    for (int i = 0; i < 100; i++) {
    			    str[i] = br.readLine();
    			    if (str[i].equals("stop"))
    				    break;
    		    }
    		    System.out.println("\\nHere is your file:");
    		    // display the lines
    		    for (int i = 0; i < 100; i++) {
    			    if (str[i].equals("stop"))
    				    break;
    			    System.out.println(str[i]);
    		    }
    	    }
        }
    but for the second i dont know how to use SESAM in the program http://cdsweb.u-strasbg.fr/cgi-bin/n...me/-oI?NGC+221
    Thanks
    Last edited by quasarLie; January 10th, 2018 at 01:45 PM.

  3. #3
    Super Moderator Norm's Avatar
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    Default Re: problem in calling a method

    Duplicate threads merged.
    i dont know how to use SESAM in the program
    Can you post all the details here so we can see what you are asking about?
    If you don't understand my answer, don't ignore it, ask a question.

  4. #4
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    Default Re: problem in calling a method

    thanks for your answer, what i want to say by sesam is just the link which contain the list of objects

  5. #5
    Super Moderator Norm's Avatar
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    Default Re: problem in calling a method

    sesam is just the link which contain the list of objects
    Is the program supposed to read an HTML page from a server, find the sesam link and use that to read a list from the server?
    If you don't understand my answer, don't ignore it, ask a question.

  6. #6
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    Default Re: problem in calling a method

    Quote Originally Posted by Norm View Post
    Is the program supposed to read an HTML page from a server, find the sesam link and use that to read a list from the server?
    I want to extrat text from an URL, and then verify if a name of object exist in it.
    I did this to extract a text
    import java.io.*;
    import java.net.*;
     
    public class Demo {
    	public static void main(String[] argv) {
    		try {
    			URL url = new URL("http://cdsweb.u-strasbg.fr/cgi-bin/nph-sesame/-oI?NGC%20221");
     
    			URLConnection con = url.openConnection();
    			System.out.println(con.getContent());
    			InputStream input = con.getInputStream();
    			while (input.available() > 0)
    				System.out.print((char) input.read());
    		} catch (MalformedURLException e) {
    			System.out.println(e);
    		} catch (IOException e) {
    			System.out.println(e);
    		}
    	}
    }
    But i dont know how to verify if a word exist in it

  7. #7
    Super Moderator Norm's Avatar
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    Default Re: problem in calling a method

    how to verify if a word exist in it
    I assume that the text read from the server via the URL is in a String. The String class has several method that can be used to search a String to see if it contains some text.
    If you don't understand my answer, don't ignore it, ask a question.

  8. #8
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    Default Re: problem in calling a method

    Quote Originally Posted by Norm View Post
    I assume that the text read from the server via the URL is in a String. The String class has several method that can be used to search a String to see if it contains some text.
    can you give me an exemple for one of the method

  9. #9
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    Default Re: problem in calling a method

    Look at the API doc for the indexOf method for an example

    If you have any questions about the code shown in the API doc, copy it and paste it here
    and ask your questions about it.
    If you don't understand my answer, don't ignore it, ask a question.

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