Thread: Problem with a tutorial program(Adding the answer of two squared numbers together)

Hi every one!

I just got a book about a week ago on Java, and its going great! I just can't find how to add an x integer squared and a y integer squared. Here is the code i currently have :

class XYZ {
    public static void main(String[] args){
        int x = 300;
        System.out.println("The squate root of "
                + x
                + " is "
                +Math.sqrt(x)
                );
        int y = 146;
        System.out.println("The square root of "
                + y
                + " is "
                +Math.sqrt(y)
                );
    }
}

What I can't seem to get right is adding the result of x and y squared, I am using a book ( Sam's Java in 24 hours, I am a Self-learning teen) to learn Java, this will be the first program I will wright on my own so please don't give the answer just an example I can use to know what is wrong or how I cloud do it (the harder the better I really want to try this with no answers on the next page).
I tried this

int z = 0;
        System.out.println("The square root of 300 + 146 is ");
        double x = y ;
        System.out.print(z);

I keep getting errors and the Net Beans IDE flags with this message
" x is already defined in main(java.lang.String[])"
I really don't have a clue what that means, please tell me anyone who knows what those message mean.


Thanks all!


-Melawe

OK lets just take a look at your current code first

int z = 0; //Here you are delaring z as 0
        System.out.println("The square root of 300 + 146 is ");//Here you are just printing out this now I doubt you want to have the numbers unchangable so you might want to do a something similar to what you did before with x and y.
        double x = y ;//This is the line that is causing you trouble and the reason is you already have a variable called x so you can't declare it again. I'm not too sure what you are trying to do here to be honest do you really want to set x = y?
        System.out.print(z);//Here you are printing out z and as you haven't changed it this will be 0

So now we need to decide what you want to do, you want to get the square root of z right? And z is x + y. So it isn't any different to what you've already done except for getting the value which is not just assigning it a number manually. I'm not sure how to help too much without just giving the answer. So maybe just in pseudocode.

Declare z
Assign z a value (x+y)
Print out preciding text
Print out square root of z

Originally Posted by Melawe

Here is an online text book InformIT: Sams Teach Yourself Java 2 in 24 Hours > Activities
It is the 4th edition thou i am using the 6th.

Ummmm OK I'm fine for books thanks . Did my last post help you in any way or confuse you more?

I think so I got what you mean I will try it asap.

Thanks

-Melawe

I tried this

System.out.println("The square root of 300 + 146 is ");
                double z = x + y;
        System.out.print(z);

and this

System.out.println("The square root of 300 + 146 is "
               + double z = x + y;
        );
        System.out.print(z);

still didn't work (the e-book link that I posted is what I am trying too do).

In both of the codes u didnt use the

Math.sqrt(int) function

this will do the job

System.out.println("The square root of 300 + 146 is ");
                double z =Math.sqrt( x + y);
        System.out.print(z);

Here is the what I get when Netbeans compiles it:

run:
The squate root of 300 is 17.320508075688775
The square root of 146 is 12.083045973594572
The square root of 300 + 146 is
0BUILD SUCCESSFUL (total time: 1 second)

It did it!

System.out.println("The square root of 300 plus the square root of 146 is ");
                double z =Math.sqrt(x + y);
        System.out.print(z);

run:
The squate root of 300 is 17.320508075688775
The square root of 146 is 12.083045973594572
The square root of 300 plus the square root of 146 is
21.118712081942874BUILD SUCCESSFUL (total time: 0 seconds)

The wrong thing in the result is that 300 and 146 squared should only be added not added then squared. :/

anyone got a clue whats wrong with it?

Originally Posted by Faz

EDIT:
Ah just re-read your last post I think I see what your trying to do now.
You want to add the squareroot of x and the square root of y not get the sqareroot of x + y.

So once again I think your assuming

Math.sqrt(x)

Is changing x but it is not.

Yea thats true, so the code should look like this at the end?

System.out.println("The square root of 300 plus the square root of 146 is ");
                double z =(x^1/2 + y^1/2 );
        System.out.print(z);

Yes, basically. Just make sure to use Math.sqrt not ^1/2 .

Okay thanks, um what IDE would you recommend? I was using Netbeans but the last few updates came with a few Trojans and other Spyware. :/

I recommend eclipse...

Okay thanks!

It worked!!! Thanks everyone!!!!

I'm glad you are all working. would you please mark this thread as solved.


Regards,
Chris

How do I do that?

Thread Tools -> Mark this thread as solved