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Thread: Java and exception handling

  1. #1
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    Default Java and exception handling

    I know I can calculate the sum of squares as such:

    // SumSquares.java: calculate the sum of two squares
    class SumSquares {
    static int sumSquares(int a, int B)/>/> {
    int asquare;
    int bsquare;
    asquare = a * a;
    bsquare = b * b;
    return asquare + bsquare;
    }
    public static void main(String[] args) {
    int x = Integer.parseInt(args[0]);
    int y = Integer.parseInt(args[1]);
    System.out.print("The sum of squares is: ");
    System.out.println(sumSquares(x,y));
    }
    }

    But how can I modify the code so that it inputs a list of integer values in the range of -100 to 100 from the keyboard and computes the sum of the squares input values. And how would I go about using exception handling to ensure that the input values are in range and are legal integers.


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    Default Re: Java and exception handling

    Welcome to the forum! Thanks for taking the time to learn how to post code correctly. If you haven't already, please read this topic to learn other useful info for new members.

    Please format/indent your code correctly. There is also an error that converted the small 'b' into a 'B' and added stray characters afterwards. I've seen this on another site but not this one, so it looks as though this code was simply copied from another forum and pasted here to get help modifying it.

    Please post your own code.

    For getting input from the keyboard, look into Scanner. You can also Google 'java exception handling' to find tutorials on how to use exceptions in Java.

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