CONDITION 1: while ( !(cChoice == 'Q' || cChoice == 'q') )
CONDITION 2: while ( cChoice != 'Q' || cChoice != 'q' )
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Java Question
CONDITION 1: while ( !(cChoice == 'Q' || cChoice == 'q') )
CONDITION 2: while ( cChoice != 'Q' || cChoice != 'q' )
Last edited by senicamarcus; April 28th, 2014 at 08:15 PM. Reason: Learning something new
Re: Java Question
what is the question?
Re: Java Question
Do Conditions 1 and 2 give the same result? What tool or technique would you use to explain the result?
Re: Java Question
not always. It depend on the value of cChoice. I assumed that you have jdk installed in you computer and you know how to create a simple program, so you can try it on yourself. just print their values giving a different value in your cChoice.Originally Posted by senicamarcus
System.out.println(!(cChoice == 'Q' || cChoice == 'q'))
System.out.println(cChoice != 'Q' || cChoice != 'q')
but first, declare a value for your cChoice. after compiling and running it, try another value for cChoice. Then after that, you can draw a conclusion of your own.
senicamarcus (April 28th, 2014)
Re: Java Question
That's the same result i was getting...I wanted to make sure i was sane...
Re: Java Question
Look at De Morgan's law
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