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Thread: Beginner Question length method

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    Default Beginner Question length method

    Given a string, return a version where all the "x" have been removed. Except an "x" at the very start or end should not be removed.

    public String stringX(String str) {
    String a = "";
    for (int i = 0; str.length()>i; i++) {
    if (!(i > 0 && i < (str.length()-1) && str.substring(i,i+1).equals("x")))
    a = a + str.charAt(i);
     
    } 
     
    return a; 
    }

    Question is in regards to the process that this statement is fulfilling for length. i < (str.length()-1) I don't understand why, without this condition, it wont check for an x in the very last variable which will return the string without the final x character if there is one.


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    Administrator copeg's Avatar
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    Default Re: Beginner Question length method

    Write it out on paper using an example. If the input string is of length 3, it's last character is at position 2. What would the final character be if the termination condition of the loop is (as written) i < (length() - 1)?

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    Super Moderator Norm's Avatar
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    Default Re: Beginner Question length method

    Another way to look at the problem: the first and last characters are always copied, only intervening 'x's are removed.
    If you don't understand my answer, don't ignore it, ask a question.

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