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Thread: Whats wrong with my code

  1. #1
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    Default Whats wrong with my code

    Hello i am a beginner please tell me
    whats wrong with my code (red colored)
    it gives me an error for 0308 that "The literal 0308 of type int is out of range"
    this error is only with 0308 and 0307
    any other digit instead of 0308 and 0307 is working

    package Loops;
     
    import java.util.Scanner;
     
    public class Mobile_Network {
     
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
     
    		Scanner num = new Scanner(System.in);
     
    		System.out.println("Enter Network Code");
     
    		int ncode = num.nextInt();
     
    		if (ncode > 0300 && ncode < [COLOR="#FF0000"]0308[/COLOR]){
    			System.out.println("Your Neywrok Sim is Jazz");
    		}
    		else if (ncode > 0321 && ncode < 0324){
    			System.out.println("Your Neywrok Sim is Warid");
    		}
    		else if (ncode > 0331 && ncode < 0337){
    			System.out.println("Your Neywrok Sim is Ufone");
    		}
    		else if (ncode > 0341 && ncode < 0347){
    			System.out.println("Your Neywrok Sim is Zong");
    		}
     
    	}
     
    }


    --- Update ---

    and how to use "or" condition here
    let say for explanation
    if (ncode == 0301 or 0302 or 0303) kind of that

    thanks in advance


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Whats wrong with my code

    The compiler treats numbers that begin with a 0 as being octal.
    The valid octal digits are 0 to 7. 0308 has an 8 that is not a valid octal digit.
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: Whats wrong with my code

    thanks
    and when i run the code after removing the error, it just ask for input, does not give any output

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: Whats wrong with my code

    after removing the error
    How was the code changed? Were ALL the octal numbers rewritten to be decimal?

    One problem in the code is there needs to be an else at the end of the if/else if chain that prints out a message saying that the value entered was not processed by any of the preceding statements.
    If you don't understand my answer, don't ignore it, ask a question.

  5. #5
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    Default Re: Whats wrong with my code

    yes the else at the end was a problem
    now it is only giving me the result of last else statment

    i also change only 0308 to 0310

    --- Update ---

    now its working fine after when i remove 0 from the start of each integer entry

    --- Update ---

    as for knowledge could you please tell me what is the problem with 0

  6. #6
    Super Moderator Norm's Avatar
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    Default Re: Whats wrong with my code

    what is the problem with 0
    0 means it is an octal number, not a decimal number
    010 octal = 8 decimal
    If the code enters a decimal number like 307 and compares it to the octal number 0307, they have different values.
    Execute this:
          System.out.println("0307="+0307); // prints int value
    If you don't understand my answer, don't ignore it, ask a question.

  7. The Following User Says Thank You to Norm For This Useful Post:

    ansiaries (April 25th, 2014)

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