you have a little problem with this statement in your constructor
Here's another way.
let say I'll pass 7.45 (as double primitive type)
First, I'll get the dollar which is 7
I'll just equate it to int or long primitive type. that way, I'll get rid of .45
int dollar = (int) 7.45; or
long dollar = (long) 7.45;
that way, variable dollar
is equal to 7
next I'll get the modulo of 7.45 in 1. that way, I can get the decimal place of the number
int cent = 7.45 % 1; or
long cent = 7.45 % 1;
that way, the value of cent
equal to 45. you just need to format it in some case, in this case the modulo is 4500...02.
then return it
return "$" + dollar + " cent" + cent;
of course there is still another way of doing that.
--- Update ---
long total_cents=(long)money*100; -- casting it to long first (7.10 becomes 7) then multiply it to 100 (becomes 700)
dollars=total_cents/100; -- 700 divided by 100 is 7 (just getting the dollar value).
cents=total_cents%100; -- you are just getting the remainder of the dollar when divided by 100.
you can do this
long total_cents=(long) (money*100); -- as you noticed, I put parenthesis in the multiplication so it means to multiply first before casting to long