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Thread: How To Make The Program Jump To The Next Function..

  1. #1
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    Question How To Make The Program Jump To The Next Function..

    Hi,

    I have the following code:

     private static LinkedList InitListA()
      {
     
          LinkedList ListA = new LinkedList();
          String Temp = null;
          int counter, buffer = 0;
     
     
            for (counter = 0; counter < MAX; counter++)
             {
              System.out.println("Enter Some Integer Values For List 'A':");
              BufferedReader InputStream = new BufferedReader(new InputStreamReader(System.in));
     
                try
                {
                  Temp = InputStream.readLine().toString();
                  buffer = Integer.parseInt(Temp);
                  ListA.add(new Integer(buffer));
     
                }}
                catch (IOException e)
                {
                  e.printStackTrace();
                }
             }
     
          return ListA;
     }

    I want InitListA() to terminate when <ENTER> is pressed with no strings keyed in.
    How do I do it ?


  2. #2
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    Default Re: How To Make The Program Jump To The Next Function..

    Hi kumarr, To make a program exit on enter, implement something like this
    public static void main(String[]args){
    		BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
    		while(true){
    			String s = null;
    			try {
    				s = br.readLine();
    			} catch (IOException e) {
    			}
     
                           if(s.length() == 0){
    				System.out.println("Exiting...");
    				System.exit(0);
    			}
     
                           // add your program logic here
     
     
              }
    	}

    cheers, wanderer(prit4u.wordpress.com)

  3. #3
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    Default Re: How To Make The Program Jump To The Next Function..

    Quote Originally Posted by Wanderer View Post
    Hi kumarr, To make a program exit on enter, implement something like this
    public static void main(String[]args){
    		BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
    		while(true){
    			String s = null;
    			try {
    				s = br.readLine();
    			} catch (IOException e) {
    			}
     
                           if(s.length() == 0){
    				System.out.println("Exiting...");
    				System.exit(0);
    			}
     
                           // add your program logic here
     
     
              }
    	}

    cheers, wanderer(prit4u.wordpress.com)
    Hey, would it work with LinkedList type ? Cuz I was getting some exceptions earlier with this same method.

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    Default Re: How To Make The Program Jump To The Next Function..

    Well if you post the final code here, I can probably look at it.

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    Default Re: How To Make The Program Jump To The Next Function..

     
    public class ExitOnEnter {
     
    	public static void main(String[]args)
            {
                LinkedList ListA = new LinkedList();
                int buffer;
     
    		BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
    		while(true){
    			System.out.println("Press enter to exit");
    			String s = null;
    			try {
    				s = br.readLine().toString();
                                    buffer = Integer.parseInt(s);
                                    ListA.add(new Integer(buffer));
     
     
     
    			} catch (IOException e) {
    				e.printStackTrace();
    			}
    			if(s.length() == 0 || isStringOfSpaces(s)){
    				System.out.println("Exiting...");
    				System.exit(0);
    			}
    		}
    	}
    	private static boolean isStringOfSpaces(String s){
    		for(char c : s.toCharArray()){
    			if(c != ' ')
    				return false;
    		}
    		return true;
    	}

  6. #6
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    Default Re: How To Make The Program Jump To The Next Function..

    System.exit() isn't a good way to terminate a program... it's much safer to simply return.

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    Default Re: How To Make The Program Jump To The Next Function..

    Well if you look at what I wrote, I told you to implement the logic after the check of s.length.
    You are getting an exception basically due to the parseInt().
    You cannot convert an empty string to an integer

    Anyway here is the final code.

    public class ExitOnEnter {
     
           public static void main(String[]args)
           {
               LinkedList ListA = new LinkedList();
               int buffer;
     
                   BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
                   while(true){
                           String s = null;                
     
                           try {                    	   
                               s = br.readLine().toString();
                            } catch (IOException e) {
    		                       e.printStackTrace();
    		                }                  
     
                           if(s.length() == 0 || isStringOfSpaces(s)){
                        	   System.out.println("ListA: "+ListA);
                               System.out.println("Exiting...");
                               return;
                           }else{
                               buffer = Integer.parseInt(s);
                               ListA.add(new Integer(buffer));
                            }           
     
                   }
     
           }
     
           private static boolean isStringOfSpaces(String s){
                   for(char c : s.toCharArray()){
                           if(c != ' ')
                                return false;
                   }
                   return true;
           }
    }

    Cheers,
    Wanderer
    [prit4u.wordpress.com]

  8. #8
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    Default Re: How To Make The Program Jump To The Next Function..

    Thanks for helloworld922 for the advice

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