Thread: A little help with my Blackjack code

Hello!

I've been working on this code and it will be really simple. it is supposed to be blackjack look a like but with 1 player that puts in 2 numbers and the one closest to 21 will be presented as winner. Anyone have som ideas to complete this code. i have 1 compilator which is keyboard.class

Anyway, here it is.

	//Blackjack
	public class Blackjack{
		public static void main(String[] args){
			System.out.print("Skriv in tal 1. ");
			double tal1 = Keyboard.readDouble();
			System.out.print("Skriv in tal 2. ");
			double tal2 = Keyboard.readDouble();
			if (tal1 == 21 && tal2 != 21){
				System.out.println("Tal 1 vann");
			}
			else if (tal2 == 21 && tal1 != 21){
				System.out.print("Tal 2 vann");
			}
			else if (tal1 < 21 && 21 < tal2){
				System.out.print("Tal 1 vann");
			}
			else {
				System.out.print("tal1 vann");
			}
		}
	}

''tal1'' is just a name for one of the numbers to put in. And so far it displays the proper winner if i enter number 21. but ''tal1'' always win no matter which numbers i put in. The thing i want is. i mount a number in booth 'tal1' and 'tal2' and the one closest to 21 is printed out as a winner. It shouldnt be that hard but i am not very good yet.

Any help is much appreciated :]

Add an if statement inside the third block to check if tal1 is bigger or if tal2 is bigger. Also, it's unnecessary to have blocks 1 and 2, simply change block three's if statement to include 21. Lastly, your else block should be printing out that it was a tie game, unless you want tie games to mean tal1 wins.

if (tal1 > 21 && tal2 > 21)
{
     System.out.println("You both busted!");
}
else if (tal1 > 21)
{
     System.out.println("Tal1 busted, Tal2 wins!");
}
else if (tal2 > 21)
{
     System.out.println("Tal2 busted, Tal1 wins!");
}
else if (tal1 > tal2)
{
     System.out.println("Tal1 wins!");
}
else if (tal2 > tal1)
{
     System.out.println("Tal2 wins!");
}
else
{
     System.out.println("The scores were tied.");
}