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Thread: a quick question . args argv.

  1. #1
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    Default a quick question . args argv.

    The code would be as such..
    import java.util.*;
    // Import for Scanner class
     
    public class test
    {
     
        public static void main(String[] args) 
    	{
     
            // TO DO code application logic here
     
            System.out.println("testing in progress::start");
     
    	if(args.length == 5)
    	// to test number of inputs
    	{	
    	System.out.println("correct number of inputs");
    		//testing for  input success.
    		if(	args[0].equals("hey") && args[1].equals("-e")		)
    		{	
    		System.out.println("testing in progress::current");
     
    		// Create Scanner object to take input from command prompt
    		//Scanner s=new Scanner(System.in); 
    		// Take input argv3 == key
     
    		String s = args[2];
     
    		// Initialize the variable count to 0
    		int count=0;
     
    		// Convert String st to char array
    		char[] c=s.toCharArray();
     
    		System.out.println(s);
     
    		// Loop till end of string
    		for(int i=0;i<s.length();i++)
     
    		//If character at index 'i' is not a space, then increment count
    		if(c[i]!=' ') count++;
     
    		//Print no.of chars other than spaces (to check space is 10 or smaller. :: yet tested)
    		System.out.println("No.of chars other than spaces are "+count);
     
    		}
    		else
    		{
    		System.out.println("testing :: error");
    		System.out.println(args[0]);
    		}
     
    	}
     
    	else
    	{
    	System.out.println("testing in progress::end");
    	}
     
    	}
     
     
     
    }
    Basically i am attempting to make use of values in argv, in string.
    currently trying to read out one input to verify data.. to code for input verification. e.g argv0 to compare a particular string input e.g that args counter should be more then 0 but not more then 10


  2. #2
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    Default Re: a quick question . args argv.

    And what problems are you having? What's your question?

  3. The Following User Says Thank You to GregBrannon For This Useful Post:

    rzzz (January 11th, 2014)

  4. #3
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    Default Re: a quick question . args argv.

    Hi Greg,

    Apologies but it has been resolved.

    Was unable to extract args values.

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