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Thread: on unary operators

  1. #1
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    Default on unary operators

    DIFFERENCE BETWEEN THESE TWO PROGRAMS PLEASE EXPLAIN ME IN DETAIL HOW IT WORKS



    public class a
    {
    public static void main(String[] args)
    {
    int i=0;
    int j=i++ +i++ + i + i;
    System.out.println(i);
    System.out.println(j);
    }
    }



    AND


    public class B
    {
    public static void main(String[] args)
    {
    int i=0;
    int j=i++ + i + i + i++;
    System.out.println(i);
    System.out.println(j);
    }
    }


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    Default Re: on unary operators

    Please read this topic to learn how to post code in code or highlight tags and other useful info for newcomers..

    These two lines:

    int j=i++ +i++ + i + i;

    int j=i++ + i + i + i++;

    are different. What about the differences don't you understand or about the results caused by them?

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    Default Re: on unary operators

    am getting different outputs and i ve doubt how i value is passing pls clear my doubt

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    Default Re: on unary operators

    Write down:

    (first line without unary operator)

    j = i + i + i + i

    substitute 0 for i, calculate j. Shat does j equal?

    write down (or modify the line in the program) to:

    j = i++ + i + i + i

    substitute 0 for i. what does that equal?

    write down (or modify the line in the program) to:

    j = i++ + i++ + i + i

    Keep going until YOU figure it out. You don't need anyone's help with adding together numbers less than 5.

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    Default Re: on unary operators

    Another way to see what each expression evaluates to and when it returns its value is to use println statements:
          int i = 1;                        //  set initial value
          System.out.println("i++="+i++);    // show value returned by i++
          System.out.println("i="+i);         //  show value AFTER i++
    If you don't understand my answer, don't ignore it, ask a question.

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