Thread: Setters and getters

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Originally Posted by Norm

The compiler is usually correct. Check why.

Without definitions and code, I can't see the what is wrong.

eggPrawn.eggPrawn.seteggPrawn

That is unusual looking and confusing code.

Yeah but the compiler is telling me that "The method geteggPrawn() is undefined for the type Pizza" yet it works for the other without an error, even though i don't have get method in pizza, it's in another class. Why would it work for one but not the other?

Originally Posted by Norm

Only answer without seeing the code is that it is coded correctly in one and incorrectly in the other.

Well i showed the code in a previous post, i've went over and over and they're definitely the same

Originally Posted by Norm

Why does the compiler find an error?

Do you know why

	boolean vegetarian = true;
				if (bacon.getType().equals("bacon")||(prawn.getType().equals("prawn"))) {
 
				 vegetarian = false;
				  System.out.println("This pizza is not Vegetarian");
			}
 
				else {
 
			     System.out.println("This pizza is Vegetarian");
				}

will work when bacon and prawn are selected, it will say this is not vegetarian, however if i say no to bacon and prawn and choose e.g. cheese it'll crash and won't appear with "this is a vegetarian pizza"

Originally Posted by Norm

You should post the full text of the error message
AND the code that causes the error.

Exception in thread "main" java.lang.NullPointerException
at PizzaChoice.main(PizzaChoice.java:150)

and if (bacon.getType().equals("bacon")||(prawn.getType() .equals("prawn"))) {

sorry about that

--- Update ---

resolved the issue

--- Update ---

Originally Posted by Norm

You should post the full text of the error message
AND the code that causes the error.

Do you know of anyway to say if the user selects an option then they can't select any others?
for example
do you want coke
do you want fanta
if they choose coke then fanta becomes unavailable, creating an illegal argument exception