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Thread: phone number generator1

  1. #1
    Junior Member yuli's Avatar
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    Default phone number generator1

    /*juliana Vargas
    programing
    10/29/2013
    */
    import java.util.Random;
    public class RandomPhoneNumber
    {
    public static void main (String[]args)
    {Random generator = new Random();


    /*write down the RandomNumber AreaCode1 AreaCode2 AreaCode3;
    *choose the first 3
    *choose the second 3
    *choose the last four
    *combine them
    */

    int RandomNumber =0;
    int exchange;
    int LastFour =0;
    int number;
    int num1 = 0;

    System.out.println(" Enter the amount of numbers you want to receive: ");
    number = generator.nextInt();

    num1 = (int)(1+Math.random()*3);
    if (num1 == 1)
    num1 = 281;
    System.out.printf(""+num1);
    if (num1 == 2)
    num1 = 713;
    System.out.printf(""+num1);
    if (num1 == 3)
    num1 = 832;
    System.out.printf(""+num1);

    RandomNumber = generator.nextInt();

    exchange =( int )(237 + Math.random() * 517);
    RandomNumber = generator.nextInt();

    while (LastFour == 1212)
    LastFour = (int) (0 + Math.random() * 9999);
    RandomNumber = generator.nextInt();

    System.out.println( "Phone numbers that resulted " +"("+num1+")" +exchange +"-"+LastFour);


    }
    }

    --- Update ---

    it wont let me input the amount of numbers I want .... and for the last 4 numbers it will always show a 0.. what is wrong


  2. #2
    Administrator copeg's Avatar
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    Default Re: phone number generator1

    Please keep all discussion to your other post.
    http://www.javaprogrammingforums.com...generator.html
    Thread locked

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