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Thread: validate a String in java Regular Expression

  1. #1
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    Default validate a String in java Regular Expression

    Dear Friends Kindly help me to validate a String in following way

    a. If first character is an alphabet, input should be Alpha Numeric 24 characters
    b. If first character is a digit, input should be minimum 15 and maximum 16 Numeric characters

    I need a regular Expression or Java program example

    Thanks in advance


  2. #2
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    Default Re: validate a String in java Regular Expression

    Why?

    You could do this without using regex. If you really need to use regex then get on and write it. It is your job not ours. make an attempt. If you get stuck post your code and ask a specific question.
    Improving the world one idiot at a time!

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    Default Re: validate a String in java Regular Expression

    Dear I made the program but not success ,
    and thanks for suggestion I will consider for next time
    Regards

    --- Update ---

    String string="PK448345678901aSSSsfry35";

    int length=string.length();

    if(string.substring(0, 1).matches("[0-9]")){
    if(length==15 ||length==16){

    System.out.println("First Character is a number..! and Length is "+string.length());
    }
    else{
    throw new InvalidSpeedException("Please Check First Character is Number or check the length");
    }
    }
    if(string.substring(0, 1).matches("[a-zA-Z]")&& matchNum.find()){
    if(matcher.find()&& length==24){
    System.out.println("First character is Character! and Length is "+string.length());
    }
    else{
    System.out.println("Exception");
    throw new InvalidSpeedException("Please Check First is Character or the length");
    }
    }

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    Default Re: validate a String in java Regular Expression

    Please read the Announcement at the top of the sub-Forums to learn how to post your code in code/formatting tags and how to ask questions that get attention and receive helpful answers.

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