I'm trying to translate from pseudocode from a textbook into java, but it's not working, so I'm clearly doing something wrong. Before I show you my code, I think it's best I give you the text, so you know exactly what I'm trying to do.

Let’s write down a more precise version of our algorithm:

ALGORITHM GRID(n)

Theinputwill be a positive whole number.

Theoutputwill be an n*n gridG. G[r,c] means the number in row r column c of the grid.

The steps to be performed are:

For eachrow r, numbered 1 up to n inclusive, and for each column c, numbered 1 up to n inclusive

do this:

Use algorithm GET-GRID-ENTRY to get the number m that we should fill into row r and column c of the grid G.

Fill in m to G[r,c]

This feels like cheating a little, we’ll need to specify what the GET-GRID-ENTRY algorithm is. Try that, in the more precise style we’ve just used for the GRID algorithm.

ALGORITHM GET-GRID-ENTRY(G,n,r,c)

Theinputwill be a partially filled in grid G, n, the size of G, and two positive whole numbers r and c

Theoutputwill be a single number m, that is the smallest number not appearing aboveG[r,c]in the same column, or to the left ofG[r,c]in the same row.

The steps to be performed are:

Let U be a piece of scratch space with n entries, with U[0,...,n] all zero.

For eachgrid entry in row r, column i, with i ranging from1up to c-1 inclusive

do this:

Let x beG[r,i]

SetU[x]to 1

For eachgrid entry in column c row j, with j ranging from1up to r-1inclusive do this:

Let y be G[j,c]

SetU[y]to 1

For each entry in U, numbered by k from 1 up to n inclusive

do this:

ifU[k]equals zero

thenStop this algorithm, and give our answer as k.

We now have a reasonably precise description of the algorithm to solve the grid problem.

These two algorithms together are supposed to create a grid of size (n*n) where each cell in that grid is the smallest possible non-negative number not already to the left or directly above that cell. I can show some examples, if people think that will make it any clearer.

Anyway, here is my attempt to code the algorithm(s)

public class GRID { public static void main(String[]args){ createGrid(4); } /** * Method for creating grid * @param n Size of grid */ public static void createGrid(int n){ //Initialize a grid of size n*n int array[][] = new int[n][n]; for (int r=0;r<array.length;r++){ for (int c=0;c<array[r].length;c++){ //Use GetGridEntry to get the required number int m =getGridEntry(array,n,r,c); //Fill in m to G[r][c] array[r][c]=m; } } //Finally, print out the grid for(int i=0;i<array.length;i++){ for(int j=0;j<array[i].length;j++){ System.out.print("\t"+array[i][j]); } System.out.println(); } } /** * Method for finding grid entry * @param G Partially filled in grid G * @param n The size of G * @param r Row Designation * @param c Column designation * @return */ public static int getGridEntry(int G[][], int n, int r, int c){ //Iniitailze the int to be returned int m =0; //Le U be a piece of scratch space with n entries, with U[0,...,n] all zero int U[]= new int[n]; //For each grid entry in row r, column i for(int gridEntry: G[r]){ //i ranging from 1 to c-1 inclusive for(int i=1;i<c;i++){ //Let x be G[r][i] int x =G[r][i]; //Set U[x] to 1 U[x]=1; } } //For each grid entry in column c row j, //with j ranging from 1 up to r-1 incluzive for(int j=0;j<r;j++){ //Let y be G[j][c] int y =G[j][c]; //Set U[y] to 1 U[y]=1; } //For each entry in U, numbered by k from 1 up to n inclusive for(int k: U){ if(U[k]==0){ m=k; return m; } } return m; } }

This code only every gives me grids with output of zeros and ones, so I must have strayed from the instructions at some point. I know that the version in the text should definitely work. I've clearly gone wrong somewhere, but can you spot where?

--- Update ---

I've just realized I shouldn't have put this here.