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Thread: Error in Java program

  1. #1
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    Default Error in Java program

    I'm trying to write a program that asks a user for their name and number. Then the program should display the name and a random number from 0 to that number. Here is the code:

    import java.util.*;

    class name {
    public static void main(String args[]){
    Random rannumber = new Random();
    Scanner input = new Scanner(System.in);
    int name, number,randomnumber;
    System.out.println("What is your name? ");
    name = input.nextInt();
    System.out.println("Give me a number: ");
    number = input.nextInt();
    System.out.println("Hi "+name);
    randomnumber = rannumber.nextInt(number);
    System.out.println("The random number from 0 and "+number+"is "+randomnumber);

    }
    }

    Program output:
    What is your name?
    test
    Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at name.main(name.java:9)


  2. #2
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    Default Re: Error in Java program

    The user is prompted to enter a name, but you're telling the scanner to expect an int.

    Should be name = input.next() or input.nexLine()

  3. #3
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    Default Re: Error in Java program

    It's says Type mismatch: cannot convert from string to int.

  4. #4
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    Default Re: Error in Java program

    you also defined name as an int at the beginning. It should be a String name, not int name.

  5. #5
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    Default Re: Error in Java program

    nvm, fixed the problem by converting the variable name to a string

  6. #6
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    Default Re: Error in Java program

    You were just told what the problem is. Reading in one type and assigning to a variable of a different type. Make sure you don't do that on every line of code.

    Slow!
    Improving the world one idiot at a time!

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