Thread: Newbie question - print out strings from input

Hi all, I'm just getting started with Java and created a simple app. Please see the code and the output. Where did I go wrong? Do I need to set the variable of "display" on top of the input? Why is the input not being stored as a variable?

import java.util.Scanner;
 
public class UserInput {
	public static void main (String args[]){
 
		Scanner jason = new Scanner(System.in);
		String fname;
		String lname;
		String addr1;
		String addr2;
		String display;
 
		System.out.println("Enter first name: ");
		fname = jason.nextLine();
		System.out.println("Enter last name: ");
		lname = jason.nextLine();
		System.out.println("Enter Address 1: ");
		addr1 = jason.nextLine();
		System.out.println("Enter Address 2: ");
		addr2 = jason.nextLine();
 
		display = ("fname, lname, addr1, addr2");
		System.out.println("The information you entered is: "+ display);
		}
}

Enter first name:
Joe
Enter last name:
Rogan
Enter Address 1:
123 Fastlane
Enter Address 2:
LA CA 90211
The information you entered is: fname, lname, addr1, addr2

display = ("fname, lname, addr1, addr2");

since you have all the variables inside one big " " you are treating them as a string instead of variables

you could do

display = fname + " " + lname + " " + addr1 + " " + addr2;

but i would imagine there is a better way but this way works lol

Thanks sleepy, that worked, but I ended up with the following to make the formatting look better:

//allow user input with Scanner utility 
import java.util.Scanner;
 
//create class named UserInput
public class UserInput {
 
	//set main
	public static void main (String args[]){
		//set scanner variable name to jason and allow system input		
		Scanner jason = new Scanner(System.in);
 
		//declare variables as strings
		String fname;
		String lname;
		String addr1;
		String addr2;
		String display;
		String answer;
 
		//get user input				
		System.out.println("Enter first name: ");
		fname = jason.nextLine();
		System.out.println("Enter last name: ");
		lname = jason.nextLine();
		System.out.println("Enter Address 1: ");
		addr1 = jason.nextLine();
		System.out.println("Enter Address 2: ");
		addr2 = jason.nextLine();
 
		//Display user input in formatted view
		System.out.println("The information you entered is: ");
		System.out.println("First Name: " + fname);
		System.out.println("Last Name: " + lname);
		System.out.println("Address 1: " + addr1);
		System.out.println("Address 2: " + addr2); 
 
		//get user confirmation data is valid
		System.out.println("Is this correct? Y/N ");
		answer = jason.nextLine();
 
		}
}

But as you can see the next operation is to get the input y/n and if "n", run the first part of the program again and get new input. If "Y", then display something like "thank you your input has been saved." How would something like that look? Back to learning more Java...

For that you use a do while loop.