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Thread: Sorting 2D Array problem

  1. #1
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    Default Sorting 2D Array problem

    Hi, I am using a bubble sort algorithm to sort a 2D array. The array is as follows:

    String data[][] = {{"John", "Smith", "14.75", "30", "ZZZZ", "ZZZZ", "ZZZZ",},{"Bill", "Gates", "18.50", "40","ZZZZ", "ZZZZ", "ZZZZ",}, 
                    {"Steve","Jobs", "10.75", "25","ZZZZ", "ZZZZ", "ZZZZ",},{"Paul", "Allen","21.50","34","ZZZZ", "ZZZZ", "ZZZZ",},
                    {"Steve", "Ballmer", "18.75", "35","ZZZZ", "ZZZZ", "ZZZZ",},{"ZZZZ", "ZZZZ", "ZZZZ", "ZZZZ"}};    
     //ZZZZ are marker values,the last row is to hold total values of all employees

    I want to sort this 2D array by comparing last names (index 1), and bubble sorting all their corresponding values along with it.

    static public String[][] sort(String data[][])
        {
            for(int x = 0; x <= data.length-1; x++)
            {
                for(int y = 0; y<=data.length-2;y++)
                {
                    if(data[y][1].compareTo(data[y+1][1]) > 0)   //compare lastnames alphabetically
                    {
                        String temp = data[y][1];    //swap last names
                        data[y][1]=data[y+1][1];
                        data[y+1][1] = temp;
     
                        String temp2 = data[y][0];  //swap first names
                        data[y][0]=data[y+1][0];
                        data[y+1][0] = temp2;
     
                        String temp3 = data[y][2];  //etc
                        data[y][2]=data[y+1][2];
                        data[y+1][2] = temp3;
     
                        String temp4 = data[y][3];
                        data[y][3]=data[y+1][3];
                        data[y+1][3] = temp4;
     
                        String temp5 = data[y][4];
                        data[y][4]=data[y+1][4];
                        data[y+1][4] = temp5;
     
                        String temp6 = data[y][5];
                        data[y][5]=data[y+1][5];
                        data[y+1][5] = temp6;
     
                    }
                }   
     
     
            }

    It compiles but when I run it i get the error:
    java.lang.ArrayIndexOutOfBoundsException: 4


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Sorting 2D Array problem

    .ArrayIndexOutOfBoundsException
    Array indexes range from 0 the the array length-1
    Check the code to see which index is going past the end of the array.
    If you can't see, add some println statements that print out the values of the indexes. The print out will show you what index is too big.

    If you had copied the full text of the error message it would show the line number of the error and the value of the index.

    Hint: the second dim can be handled as a single dim array
    int[][] twoDim = {{1,2,3}, {4,5,6}};
    //  swap the one dim array parts
    int[] oneDimTemp = twoDim[0];  //  save
    twoDim[0] = twoDim[1];  // move
    twoDim[1] = oneDimTemp;
    System.out.println(Arrays.deepToString(twoDim));// [[4, 5, 6], [1, 2, 3]]
    If you don't understand my answer, don't ignore it, ask a question.

  3. The Following User Says Thank You to Norm For This Useful Post:

    lordofrandom (May 4th, 2013)

  4. #3
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    Default Re: Sorting 2D Array problem

    Quote Originally Posted by Norm View Post
    Array indexes range from 0 the the array length-1
    Check the code to see which index is going past the end of the array.
    If you can't see, add some println statements that print out the values of the indexes. The print out will show you what index is too big.

    If you had copied the full text of the error message it would show the line number of the error and the value of the index.

    Hint: the second dim can be handled as a single dim array
    int[][] twoDim = {{1,2,3}, {4,5,6}};
    //  swap the one dim array parts
    int[] oneDimTemp = twoDim[0];  //  save
    twoDim[0] = twoDim[1];  // move
    twoDim[1] = oneDimTemp;
    System.out.println(Arrays.deepToString(twoDim));// [[4, 5, 6], [1, 2, 3]]
    Thanks a lot, sir.

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