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Thread: Java sequential search.

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    Default Java sequential search.

    I'm working on sequential search and this is my code to search a String. The problem I have is that once the array is found, it stop. I was wondering what if there are more than one occurrence of that String in the array. I'm trying to modify my code so it find all the occurence and print it. I thought of removing the "break" but then even if I remove it, the code would replace the "found" index by the next occurence that it find, so my program results in printing the last match that it find instead of all of them. Can anyone help me fix this? Thanks
    public static void findPerson(Assignment[] r, String toFind)
    	{
    	    int found = -1;
     
    	    for(int i = 0; i < r.length; i++)
    	       if (r[i].getPerson().compareTo(toFind) == 0)
    	           {
    	               found = i;
    	               break;
    	           }
            if (found != -1)
            {  // we have found the person
               System.out.println("We found " + toFind + " in the roster: ");
               System.out.println(r[found]);
            }
            else
               System.out.println(toFind + " is not in the roster");
    	}


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    Default Re: Java sequential search.

    Put the "found" indexes in an ArrayList.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Java sequential search.

    I .add(found) onto the arrayList, is there a way to check if an ArrayList contains elements? Since the "found" only get added when the String match, if there no string match then there be nothing inside the list, so I want to check whether the list contains elements. Thanks

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    Default Re: Java sequential search.

    way to check if an ArrayList contains elements?
    The ArrayList class has lots of useful methods. Read the API doc to see what will work for you.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Java sequential search.

    Found it. Thanks!

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