Thread: Digit counter

Hi everyone, this is my very first post here in jpforums .

Sorry if is not an allowed question,but, there is another way to do this more simple??? (I am a begginner) I suspice that my code is too long and useless. I only want to count the digits that a number has.

]
 	static int contarCifras(int num){
 
		int cifras = 1;
 
 
		String[] nums = new String[8];
 
		// I initialize array to 0   to avoid it start on null, when I convert to integer I get exception
		for(int i=0;i<nums.length;i++)
			nums[i]="9";
 
		// I add the string "9" to every string of the array
		for(int i = 0; i <nums.length;i++)
			for(int j = 1; j<=i;j++)
				nums[i] +="9";
 
		// I compare if a number is higher than 9, if it is higher, it means it has 2 digit, if higher than 99... 3....  
		for(int i = 0;i <nums.length;i++){
			if(num>Integer.parseInt(nums[i]))
				cifras++;
			else
				break;
		}
		return cifras;
}

1º question: I don't know another way to "append" 9 to an integer, if i 9+9 = "18" but i want start at number 9 and append 9 many times, then = "99", next "999"

2º question: It is necesary to start array of strings to "9"?? because I see with debugger that it is null as default so when i append 9 , it is "null9"
and when I parse to integer it throw me "numberformatexception"

thank you.

thank you, I'll not forget about to set strings as: "" when needed,