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Thread: Introduction to programing class. I am stuck on my assignment arrays.

  1. #1
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    Default Introduction to programing class. I am stuck on my assignment arrays.

    I have an array assignment that I am stuck on. This is the assignment. This is my first time posting here, but I have gained alot of information from the other posts.

    Create a program that asks the user how many students there are. Then, for each student, ask for a student id, the first name, last name, and score (must be between 0 and 100 to be valid). When all the data has been entered, calculate and display the average. Allow the user to search for a student by entering a student id. If the student id is valid and a student is found, display the student's full name, score, and deviation of the score from the average. If the student has the highest score, display a message indicating that. Continue asking the user to search for students until the user enters "quit", at which point the program should exit.

    The following is the code I have so far. I am not sure how to search the arrays and also how to return all the information from the different arrays.

    import java.util.Scanner;
     
    public class Assn06 {
     
    	public static void main(String[] args) {
    		Scanner input = new Scanner(System.in);
     
    // User input number of students	
    		System.out.print("Enter the number of students");
    		int studentNumber=input.nextInt();
     
    		int sum = 0;
     
    // Array for student ID
    		int[] studentid = new int[studentNumber];
    		String[] firstname = new String[studentNumber];
    		String[] lastname = new String[studentNumber];
    		int[] studentscore = new int[studentNumber];
    		int i;
    		for ( i = 0 ; i < studentNumber ; i++)
    		{
    			studentscore[i] = studentid[i];
    			firstname[i] = lastname[i];
    			System.out.printf("Enter student %d ID : ", i+1);
    			int studentId = input.nextInt();			
    			studentid[i] = studentId;
     
    			System.out.printf("Enter student %d first name : ", i+1);
    			String studentFirstname = input.next();
    			firstname[i] = studentFirstname;
     
    			System.out.printf("Enter student %d last name : ", i+1);
    			String studentLastname = input.next();
    			lastname[i] = studentLastname;		
     
    			System.out.printf("Enter student %d score : ", i+1);
    			int studentScore = input.nextInt();
    			studentid[i] = studentScore;
    			sum += studentScore;		
    		}	
     
    //Calculate Average
    		int average = sum / studentNumber;
     
    //Display Average
    		System.out.println("The student average is " + average);
     
    // Search by student Id
     
    		System.out.printf("Search for student by entering ID: ");
    		int studentIdsearch = input.nextInt();
     
     
     public static int linearSearch(studentid, studentIdsearch)
    {
     
    	for (int j = 0 ; j < list.length; j++)
    	{
    		if (studentIdsearch == list[j])
    			return j;
    	}
    }
     
     
     
    	}
     
    }


  2. #2
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    Default Re: Introduction to programing class. I am stuck on my assignment arrays.

    Hi. I understand you are in an intro class, and while your implementation will work for the purpose of this assignment, have you thought about using a separate class to hold all the information for a student? If you do not know what I am talking about, just forget everything I have said and read on..

    You are off to a good start. You have this:
    public static int linearSearch(studentid, studentIdsearch)
    {
     
    	for (int j = 0 ; j < list.length; j++)
    	{
    		if (studentIdsearch == list[j])
    			return j;
    	}
    }
    Let us utilize this method for search. Start with the most basic criteria: Allow the user to search for a student by entering a student id. First, which array would you use to search for IDs? The array that holds IDs, of course: studentid! Now, how would you use that for-loop with studentid[]? When do you stop searching? What do you do when you find the ID? Utilize the linearSearch(.., ...) method -- it is all there for you; you just need to fill everything in!

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