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Thread: Java basic Example

  1. #1
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    Unhappy Java basic Example

    <code=java>

    i m giving again a very simple code of odd or even . I want that user should give the value of x and thereafter ,it is checked whether odd or even.

    class oddoreven
    {
    public static void main (String args[])
    {
    int x;

    System.out.println ("Enter an integer to check if it is even or odd ");
    if(x%2==0)
    System.out.println("you entered an even number ,");
    else
    System.out.println("You entered an odd number .");
    }
    }
    In this prog user should give the value of x and it is then checked. But i m getting an error that variable x might not have been initialized. Thanks


  2. #2
    Super Moderator curmudgeon's Avatar
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    Default Re: Java basic Example

    You don't seem to get input from the user anywhere in your program, and the compiler is smart enough to see that you're not giving x any value. Consider using a Scanner object for this.

  3. #3
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    Default Re: Java basic Example

    can u help me in writing the code for this ?

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    Default Re: Java basic Example

    No.
    Give X a value and read up on the Scanner class.

    Sorted.
    Please use [highlight=Java]//code goes here...[/highlight] tags when posting your code

  5. #5
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    Default Re: Java basic Example

    Hi,
    You can use System.in to read values from console.
    thus get X value from user and pass that to determine whether odd or even.

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