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Thread: Sequence Classification

  1. #1
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    Default Sequence Classification

    Hey guys,

    Just made a small new program off one I made earlier, it asks you for a sequence and then classifies it to be either arithmetic or geometric or nothing. Here is the code:

    import java.util.Scanner;
     
    public class ArithmeticSequenceClassification {
     
    	public static void main(String[] args) {
     
    		int[] sequence = new int[4];
    		int num1, num2, num3, num4, num5;
    		int d;
    		int n;
    		boolean isArithmetic, isGeometric, isNothing;
    		String output;
     
    		Scanner scan = new Scanner(System.in);
     
    		System.out.println("Please enter 5 numbers. Your inputs will be scanned and classified by their sequence attributes.");
    		System.out.print("Enter your first number: ");
    		num1 = scan.nextInt();
     
    		System.out.print("Enter your second number: ");
    		num2 = scan.nextInt();
     
    		System.out.print("Enter your third number: ");
    		num3 = scan.nextInt();
     
    		System.out.print("Enter your fourth number: ");
    		num4 = scan.nextInt();
     
    		System.out.print("Enter your last number: ");
    		num5 = scan.nextInt();
     
    		sequence[0] = num1;
    		sequence[1] = num2;
    		sequence[2] = num3;
    		sequence[3] = num4;
    		sequence[4] = num5;
     
    		d = num2 - num1;
    		n = num2 * num3;
     
    		if(num2 - num1 == d) {
     
    			if(num3 - num2 == d) {
     
    				if(num4 - num3 == d) {
     
    					if(num5 - num4 == d) {
     
    						isArithmetic = true;
    						isGeometric = false;
    						isNothing = false;
     
    					}
     
    				}
     
    			}
     
    		}
     
    		else if(num2 / num1 == n && num2 % num1 == 0) {
     
    			if(num3 / num2 == n && num3 % num2 == 0) {
     
    				if(num4 / num3 == n && num4 % num3 == 0) {
     
    					if(num5 / num4 == n && num5 % num4 == 0) {
     
    						isGeometric = true;
    						isArithmetic = false;
    						isNothing = false;
     
    					}
     
    				}
     
    			}
     
    		}
     
    		else {
     
    			isArithmetic = false;
    			isGeometric = false;
    			isNothing = true;
     
    		}
     
    		if(isArithmetic = true) {
     
    			output = "Your sequence was: Arithmetic.";
     
    		}
     
    		else if(isGeometric = true) {
     
    			output = "Your sequence was: Geometric.";
     
    		}
     
    		else {
     
    			output = "Your sequence was not a sequence.";
     
    		}
     
    		System.out.print(output);
     
    	}
     
    }

    I cannot see any possible errors within the program, and neither does Eclipse. However, when I run it, it will not accept my number inputs and go on to asking for the next number!

    Help please?

    -Silent
    Last edited by SilentNite17; May 31st, 2012 at 08:42 PM. Reason: Spelling Error


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Sequence Classification

    Can you post the console's contents from when you execute the program.

    I suspect that you are having problems with the Scanner class not emptying its buffer of the line end character. For a test enter all your input on one line before pressing Enter.
    To make the Scanner class get rid of the line end character in its buffer, call the nextLine() method.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Sequence Classification

    OK, Let me try that.

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    Default Re: Sequence Classification

    It will not accept it, as the variable of num1 etc is int, not String.

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    Default Re: Sequence Classification

    Can you post the console's contents from when you execute the program.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Sequence Classification

    OK, here is what happens.

    It prints what it it supposed to:

    Please enter 5 numbers. Your inputs will be scanned and classified by their sequence attributes.
    Enter your first number:

    Then when I enter a number and press enter, the console skips to a new line without typing or printing anything new.

  7. #7
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    Default Re: Sequence Classification

    Did you try as I suggested? enter all 5 numbers BEFORE pressing Enter?
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Sequence Classification

    Try this change in your sequence declaration in main:
    int[] sequence = new int[5];

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    Default Re: Sequence Classification

    @razorsknife You're getting ahead of the OP. He hasn't reported the exception yet.
    If you don't understand my answer, don't ignore it, ask a question.

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