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Thread: Overloading Method

  1. #1
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    Default Overloading Method

    Hi I am trying to call a method to compute 1 - 3 + 5 - 7 + .. .. - (n - 2) + n
    For example: n = 9 the Series would look like 1 - 3 + 5 - 7 + 9 = 5


    I am not looking to get spoon fed. Just hoping someone could help me understand the logic and let me know if I am even close.

    Here is what I have so far.


    import javax.swing.JOptionPane;


    public class OddSum {

    public static void main(String[] args) {


    int oddSeries, m, n;
    String num1Str, num2Str;

    // Get a pair of positive Integers from users
    num1Str = JOptionPane.showInputDialog("Enter a positive integer:");
    m = Integer.parseInt(num1Str);
    num2Str = JOptionPane.showInputDialog("Enter a positive integer:");
    n = Integer.parseInt(num2Str);

    // Call a method to compute 1 - 3 + 5 - 7 + .. .. - (n - 2) + n

    oddSeries = myOddNum(n);

    // output the result
    System.out.println("(OddNum) The series of 1 to " + n + " = " + oddSeries);
    }


    // Method myOddNum with on Parameter
    public static int myOddNum(int myN) {

    int localSum, oddnum;

    localSum = 0;
    oddnum = 0;
    for (int i = 1; i <= myN; i++) {
    if (i%2 != 0);{
    oddnum = myN - 2;}
    localSum = localSum + oddnum;}
    return localSum;
    }
    }


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    Default Re: Overloading Method

    Rephrase your question and surround your code in highlight tags.
    What problems are you getting? and what does Overloading have to do with your question?
    Please use [highlight=Java]//code goes here...[/highlight] tags when posting your code

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