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Thread: String.split("") puts null in the first index

  1. #1
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    Default String.split("") puts null in the first index

    So I have absolutely no idea why this is happening, hopefully someone can help me out. I'm a novice programmer, and lately I've noticed that whenever i use String.split() with "" as a delimiter, the first index will be null and the second index will contain the first element, and so on. Here's an example of some output i've been seeing:

    public class wtf
    {
    	public static void main(String[] args)
    	{
    		String mystring = "hello";
    		String[] myarray = mystring.split("");
    		for(int i=0; i<myarray.length;i++)
    			System.out.println(i + ": "+ myarray[i]);
    	}
    }


    OUTPUT:
    0:
    1: h
    2: e
    3: l
    4: l
    5: o


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: String.split("") puts null in the first index

    The first element in the array looks like an empty String, not null.
    I don't understand regular expressions to be able to tell you what an empty regexp String will do.

  3. #3
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    Default Re: String.split("") puts null in the first index

    use trim before apply split function. let me know if it doe'st not solve your problem

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: String.split("") puts null in the first index

    I don't see a blank in the String that the OP posted. Do you? What would trim do with no spaces?

  5. #5
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    Default Re: String.split("") puts null in the first index

    this is probably too late to get another response, but kB18001 I tried String.trim() first but to no avail, I get the same output

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