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Thread: 0 seems to be comming out as 48?

  1. #1
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    Default 0 seems to be comming out as 48?

    I have writen the following code but for some reason all the numbers seem to be offset by 48?

    String bdString;
    Vector<Integer> v = new Vector<Integer>();
     
    BigDecimal bd = new BigDecimal(Math.pow(2, 1000));
    bdString = bd.toString();
     
    for (int i = 0; i < bdString.length(); i++) {
    	v.add((Integer.valueOf(bdString.charAt(i)).intValue()));
    }

    When I check the vector all 0's have been entered in as 48, all 1's have been entered in as 49, 2's as 50 etc. I know I'm going to feel like a fool when somebody points it out but... What is going on?


  2. #2
    Senile Half-Wit Freaky Chris's Avatar
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    Default Re: 0 seems to be comming out as 48?

    Hi tarkal,

    a char is stored as an int, thus when using Integer.valueOf(), you are essentially requesting the value of another interger, in ASCII 48 is the integer number of the character '0'. So you could just subtract 48 from each number, or consider the following method:

    Character.getNumericValue()

    Chris
    chris[at]javaprogrammingforums[dot]com

    Prifysgol Bangor University, North Wales

  3. The Following User Says Thank You to Freaky Chris For This Useful Post:

    tarkal (November 13th, 2011)

  4. #3
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    Default Re: 0 seems to be comming out as 48?

    Ooooo I like the look of Character.getNumericValue().

    Thanks