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Thread: help me how to convert it to "2d to 1d"

  1. #1
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    Post help me how to convert it to "2d to 1d"

    import java.io.*;
    public class Dionisio_RProgram2 {
    public static void print_array(int[][] numbers)
    {

    for (int i=1; i<numbers.length; i++) {
    System.out.print("" + i + " |");
    for (int a=1; a<numbers[i].length; a++)
    System.out.print("\t" + numbers[i][a]);
    System.out.println(); }

    }

    public static void main(String[] args) throws IOException {
    BufferedReader r =
    new BufferedReader (new InputStreamReader(System.in));

    String yesno="u";
    boolean isExit=false;

    do{

    String row, column;
    int Columns = 0;
    int Rows = 0;
    System.out.print("\n");
    System.out.print("ENTER A NUMBER : ");
    row= r.readLine();
    Rows= Integer.parseInt( row );


    int values[][] = new int[Rows+1][Rows+1];
    int [][] m = new int[Rows][];
    for (int i=0; i < Rows; i++)
    m[i] = new int[Rows];
    for (int i=0; i < values.length; i++)
    for (int a=0; a < values[i].length; a++)
    values[i][a] = i*a;
    System.out.print("\n");
    for (int i=0; i < values.length; i++){
    System.out.print(" " + i + " ");
    }
    System.out.println();
    for (int i=0; i < values.length; i++){
    System.out.print("" + "" + "---");
    }
    System.out.println();
    print_array(values);
    System.out.print("\n\n");

    System.out.println("Try again (press 1 if yes/press 2 if no)?");
    yesno = r.readLine();

    if(yesno.equalsIgnoreCase("1")) {
    isExit=false;
    } else if(yesno.equalsIgnoreCase("2")) {
    isExit=true;
    }

    }while(!isExit);
    System.out.print("Goodbye!");


    }
    }


  2. #2
    Administrator copeg's Avatar
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    Default Re: help me how to convert it to "2d to 1d"

    Well, since this is marked as solved I take it that it is solved. But for the record, I recommend reading the following:
    How to Help Yourself Get Help

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