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Thread: Need basic String help

  1. #1
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    Default Need basic String help

    This is basic stuff, but I'm stuck, and inexperienced. I'm working w/ Scanner and I made a string to scan the full name of a user.

    import java.util.Scanner;
     
    public class ThreeNamesNextLine
    {
    	public static void main (String [] args)
    	{
    	Scanner scan = new Scanner(System.in);
     
    	System.out.print("Please enter your name: ");
    	String fullName = scan.nextLine();

    I need to break the string down to acquire the first initials of the user when he/she enters their first, middle, and last names (there is a space between each name). So far this is what I have, which gives me the first and middle initials, how do I get the last?

            String middleInitial;
    	String lastInitial;
    	String firstLetter = fullName.substring(0,1); // for the first initial
            String lookFor = " ";
    	int space1; // indicates first space after first name is entered
     
    	space1 = fullName.indexOf( lookFor );
    	middleInitial = fullName.substring(space1 +1);
     
    	String realMiddleInitial; // don't know how to shortcut this so I had to make a new String
    	realMiddleInitial = middleInitial.substring(0,1);
     
            firstLetter = firstLetter.toUpperCase();
    	realMiddleInitial = realMiddleInitial.toUpperCase();

    It's ugly yeah, but yet again, I'm new. Thanks in advance for the help.
    Last edited by Sadalmelik; September 18th, 2011 at 12:58 AM.


  2. #2
    Super Moderator Sean4u's Avatar
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    Default Re: Need basic String help

    Unless you use java.util.regex.Pattern, this is what you'd have to do. You could possibly also try java.lang.String.split(). If you want to go with what you've got, what you need to do is to restart your search for a name-breaking character (space? dot?) from the point you last found one. There's another method called indexOf in java.lang.String which allows you to start indexOf from a specified point in the string. You saved the last position of a space in 'space1'. I reckon you'll work the rest out for yourself!

  3. The Following User Says Thank You to Sean4u For This Useful Post:

    Sadalmelik (September 18th, 2011)

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