Jumps over one scanner in if else loop

[MikalD]

See the comment in code nearly at bottom in code.
Here is my code:

import java.util.Scanner;
 
public class lanparty {
	public static void main(String args []) {
 
			Scanner in = new Scanner (System.in);
 
			String fornavn;
			String fortlf;
			String deltagernummer;
			String navn;
			String adresse;
			String tlf;
			String epost;
			String skole;
			int alder;
 
			System.out.println("Svar på følgene spørsmål!");
			System.out.println("Deltagernummer ");
			deltagernummer = in.nextLine();
			System.out.println("Navn ");
			navn = in.nextLine();
			System.out.println("Adresse ");
			adresse = in.nextLine();
			System.out.println("Telefon nummer ");
			tlf = in.nextLine();
			System.out.println("Epost adresse");
			epost = in.nextLine();
			System.out.println("Skole");
			skole = in.nextLine();
			System.out.println("Alder");
			alder = in.nextInt();
 
			if (alder >= 18){
				System.out.println("Følgene informasjon er lagret:  ");
				System.out.println("Deltagernummer: "+ deltagernummer);
				System.out.println("Ditt navn: " + navn);
				System.out.println("Din adresse er: "+ adresse);
				System.out.println("Telefon nummer er: "+ tlf);
				System.out.println("Din epost adresse: "+ epost);
				System.out.println("Skolen du går på er: "+ skole);
				System.out.println("Din alder er: "+ alder);
			}
			else{
				System.out.println("Siden du er under 18 må vi ha navn og tlf nummer til foresatte ");
				System.out.println("Navn: ");
				fornavn = in.nextLine(); //When i compile and run this is getting skipped. It just prints the text but dont wait for inndata.
				System.out.println("Telefon: ");
				fortlf = in.nextLine();
				System.out.println("Følgene informasjon er lagret:  ");
				System.out.println("Deltagernummer: "+ deltagernummer);
				System.out.println("Ditt navn: " + navn);
				System.out.println("Din adresse er: "+ adresse);
				System.out.println("Telefon nummer er: "+ tlf);
				System.out.println("Din epost adresse: "+ epost);
				System.out.println("Skolen du går på er: "+ skole);
				System.out.println("Din alder er: "+ alder);
				System.out.println("Foresattes navn: "+ fornavn);
				System.out.println("Foresattes Telefon Nummer: "+ fortlf);
			}
 
 
 
 
 
	}
 
}

[Norm]

The Scanner class is tricky to use. It reads what you type in into a buffer and then returns the next token for next... calls and the whole buffer for nextLine(). If you don't clear out the newline chars after some nextInt calls the nextLine will return the empty line up to the newline char.

Write a small test program that uses different combinations of next... and nextLine and has... methods to see how it works. For example if you are using nextInt for several inputs, you can type all of the numbers on one line before pressing Enter. For example: 33 44 55 on one line would feed three nextInt calls.

[Tjstretch]

Unless required, the Scanner class is unreliable to most beginners. A good replacement is JOptionPane; If you haven't seen it before, check out here.

[dlorde]

Unless required, the Scanner class is unreliable to most beginners.

It's reliable for everyone if used correctly. The API docs describe exactly how it behaves and it behaves as described in the API docs.

A good replacement is JOptionPane; If you haven't seen it before, check out here.

Be aware that they are quite different forms of input - Scanner is a (in this usage, command line) token parser, JOptionPane is a GUI dialog box, not necessarily a suitable replacement for Scanner at all...

[MikalD]

Thanks for all replies. So the thing I need is i print out a question and they answer. I need to collect 1 int value and rest string. Because I need to determine there age in the if, else statement. If I ask about there age first like age = in.nextInt();
and after that just in.nextLine();
would the problem might disepear then?

[Norm]

would the problem might disepear then?

Write a small test program that uses different combinations of next... and nextLine and has... methods to see how it works.