Lost on Java Threads

[help_desk]

Hello,

Please, this question is from the OCP Java SE 6 Programmer Practice Exams textbook, Assessment Test 2 question 8. Below is the code for the question.

public class Salmon extends Thread {
 
	public static long id;
 
	public void run(){
		for(int i=0; i<4;i++){
			if(i==2 && id==Thread.currentThread().getId()){
				new Thread(new Salmon()).start();
				throw new Error();
			}
			System.out.print(i + " ");
			System.out.println("programme got past Error!!");
		}
	}
	public static void main(String[] args) {
 
		Thread t1 = new Salmon();
		id = t1.getId();
		t1.start();
	}
 
}

When I ran the code, below is my output:

0
programme got past Error!!
1
programme got past Error!!
Exception in thread "Thread-0" java.lang.Error
at org.OCP.JSE6.Exercises.Assessment1.Salmon.run(Salm on.java:15)
0
programme got past Error!!
1
programme got past Error!!
2
programme got past Error!!
3
programme got past Error!!

My questions are as follow:
1.why was there an exception in thread after i was 1 and then the programme continued again. I just want to understand the output.

2. I thought since there was an exception, the programme should crash but that wasn't the case, the programme continued after the new Error() statement. Why is this?

Thanks

[KevinWorkman]

1: Because you're creating another Thread. Only the first Thread will hit the Exception.

2: The Thread that encountered the Exception will exit. The rest will not.