Patterns!! Please help!

[winn1me]

I've been trying to write a program for the last 3 hours with no success. What probably should seem easy to most I'm having difficulty with. I have to print two separate patterns on the same program.

I've selected the following two:

1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6


1 2 3 4 5 6
X 1 2 3 4 5
X X 1 2 3 4
X X X 1 2 3
X X X X 1 2
X X X X X 1

Imagine the X's are not there on the one above. Every time I previewed the post it showed it a different way without the X's.

This is the two patterns stacked up, any ideas?

Here's what I have so far and it gets me to the first line of pattern 2:

public class TwoPatterns {
public static void main(String[] args) {

for (int a = 1; a <= 6; a++) {
for (int b = 1; b <= a; b++) {
System.out.printf("%-4d", b);
}
System.out.println();
}
for (int c = 6; c >= 6; c--) {
for (int d = 1; d <= c; d++) {
System.out.printf("%-4d", d);
}
System.out.println();
}
}
}

any help would be so appreciated!

[Junky]

On each line you need to print M number of spaces before you start printing the numbers. Surely you can see a pattern in how many spaces are needed.

[winn1me]

On each line you need to print M number of spaces before you start printing the numbers. Surely you can see a pattern in how many spaces are needed.

I understand that I need to probably have an if/else statement in there that displays a space (" ") if the column is less than or equal to the row but I'm not sure where to put it. I played around with a loop after the second set of nested fors but I could never get it to print what I needed, it seemed to always print on the same line as the first set.

I then tried to enter in more println but that obviously didn't do the trick, it just spaced out my program more. Do I not need the 3rd and 4th for loops? Should I be doing the if loop directly after the 2nd for loop?

--- Update ---

This is the other version I was playing with:

public class TestPatterns {
public static void main(String[] args) {

//Set how many rows you want per pattern
int column = 12;

for (int a = 1; a <= column; a++) {

for (int b = 1; b <= column; b++) {
if(b < a)
System.out.print(" ");
else
System.out.printf("%-4d", b);
}
System.out.println();
}
}
}

[syedfahadjalali]

try this

for(int i=1;i<7;i++){
 
   for(int k=1;k<=i;k++)
     System.out.print(k);
 
      System.out.println()  ///// for LINE Breaking Work With Outer Loop
     } 
 
 
second petren 
 
for(int i=1;i<7;i++){
 
   for(int k=1;k<i;k++)
     System.out.print(" ");
   for(int m=6;m<=i; m++)
      System.out.print(m)
 
      System.out.println()  ///// for LINE Breaking Work With Outer Loop
     }

[Norm]

@syedfahadjalali Please don't spoonfeed code

[winn1me]

Although that's helpful, Norm is right. I'm looking for the logic so I can understand how to code this in the future. I am, however; grateful for your post, unlike some that assume everyone knows.

Mike

[copeg]

Suggested reading to @winn1me and @syedfahadjalali
http://www.javaprogrammingforums.com...n-feeding.html

[syedfahadjalali]

Extremely Sorry. i will be carefull

[Junky]

This type of exercises always pop up. One way to handle them is to write a method that takes two parameters: a char (the character to be printed) and an int (the number of times to print that character). In your main method you simply call your helper method passing in a space and the number of times it has to be printed. If you use some sort of counter then you need to increment or decrement it. Then you can print out the digits.