How do improve the accuracy of this averaging program

[Alge4]

Hello,

My first post, been following a set of tutorials online. And it had been writing an averager, were the number of values to be summed was defined in the code. I wanted this to be "user" set. So I attempted to give it a go. I got quite far through it and ran this. It was at that moment i realized I had an inaccuracy because i had absorbed each number as an int type. What i would like to do is to swap it out so that the program can output a decimal. I understand that this will mean i will have to use floats and doubles. But no idea how because most of what I've done has been copied (/tweaked) from examples within the course.

If anyone could help me alter this code so that it will handle decimal places and output decimal results that would be a great help.

Alge4

package averager;
import java.util.ArrayList;
import javax.swing.JOptionPane;
 
public class Averager {
    public static void main(String[] args) {
        //Declare variables
        ArrayList<Integer> list = new ArrayList<Integer>() ;
        int Number, i;
        int total =0;
        int average = 0;
        Number =  Integer.parseInt(JOptionPane.showInputDialog("Please the total amount of numbers to be averaged."));
        int[] grid = new int[Number];
        i =0;
        while(i < Number ){
           list.add(Integer.parseInt(JOptionPane.showInputDialog("Please enter number" + (i+1) + "of the numbers to be averaged.")));
           i++;
        }
        for(i=0;i<Number;i++){
            grid[i]= list.get(i);
 
        }
        for(i=0;i<Number;i++){
            total = grid[i]+total;
        }
        average= total/Number;
        JOptionPane.showMessageDialog(null,"The average of your "+Number+" Number(s) is: "+average);
 
    }
}

[jps]

It was at that moment i realized I had an inaccuracy because i had absorbed each number as an int type.

Start there. Then work on upgrading the math and the output

[Junky]

You can still have all the values as ints. When it comes to calculating the average you need at least one floating point value.

9 / 2 = int
9.0 / 2 = double
9 / 2.0 = double
9.0 / 2.0 = double

Easiest solution for you would be to have the denominator as a double.