Help me understand what the print out sequence is please

[LeaAnn0223]

public class Sequence { 
Sequence() { System.out.print("c "); } 
{ System.out.print("y "); } 
public static void main(String[] args) { 
new Sequence().go(); 
} 
void go() { System.out.print("g "); } 
static { System.out.print("x "); } 
}

so that's the code and the print out sequence is xycg .....what is it that is driving the sequence output to do it in this order?

thanks

[Norm]

Format the code so it is readable then put comments next to each println in the order that they are executed.

[LeaAnn0223]

that is a sample question on a java certification test.....are you saying that this code is not written out properly even though it runs correctly?

[Norm]

What I mean is that the poor, cramped formatting of the code makes it hard to read. Properly formatted code is much easier to read and understand.
The added comments will help you read the code to more easily see what order the statements are executed in.

Read this about initialization:
http://docs.oracle.com/javase/tutori...O/initial.html

[LeaAnn0223]

The funny thing is, Norm, I got that sample question from Oracle lol. That's a sample pull straight from their website for SE7 programmer exam lol So if that's the way they're going to formulate their questions....they're just making it harder for the person taking the tests.

[Norm]

Whoever wrote it doesn't change it from being poorly formatted.

[Bhawani]

The output will be :
x c g
First the static block will print, then the constructor, and finally the go() will print