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  1. Replies
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    Re: help on this...

    uhh ok nevermind i got it thanks :)
  2. Replies
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    Re: help on this...

    so do i just create a double variable like

    double tmp = 0.3;

    to use 1/3?
  3. Replies
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    help on this...

    i have this statement

    pi = 4*(1-(1/3))

    then i print it out.. pi is a double set to 0..

    but it keeps printing out 4.0

    instead of 2.6666666667 :( help
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