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So, y is not a reference variable? It doesn't have an address for an object? Seems like the normal variables. If you excute my code you will see my point.

Cornix: I have two classes in my code.

--- Update ---

My code has no error. Please, understand my point. y and z are both references to objects but I can only print one of them.

y is supposed to be an address that refers to a String object, why cannot I print it out like I did to z?
Is there a difference between objects of built - in classes and the other objects?

How could I get the String "mummy" again after changing the reference variable?

Check out this code:


class cat1 {
int x;
}

class tot {

Thanks.

I have read that the contents of a String object are immutable, but I could change them as I wish, check this out:

class a {
public static void main (String args []) {
String x=...

Thanks a lot to all of you

--- Update ---

I just thought that the j variable of for, would has been put directly in the generator method, it seems that it must be put into the instance variable...

Hi

It is in Java.

class fd {
int x;
void generator (int i){ fd o=new fd (i);}
}

class ibj2 {