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yes, x and y


after point 1 is projected, the right distance is the distance between point 1 and point 2 is the distance in the original space.


For example
Point 1 is (0,0)
Point 2 is...

Yea, the 3rd point is equidistant from 1 and 2, so the 2 solutions are a positive and negative y, is it? then i will take the positive one. But how can i do this?

The algorithm is
Pick a point and put it at the origin (0,0)
Put the second point to the right distance away from the 1st point (0, distance(Point 1, Point 2))
The 3rd point is the intersect of...

yea, i dont know how to start doing this program....

Hi
i am working on information visualization, which use triangle projection to do it, that get n points from a higher dimensional space to a 2 dimensional space. i need to project points from an...