Because of some hideous black compiler magic running in the background.
You write:
System.out.println('1'+2+"2");
but what the compiler does with it is something like this:
char a = '1';...
Type: Posts; User: Cornix
Because of some hideous black compiler magic running in the background.
You write:
System.out.println('1'+2+"2");
but what the compiler does with it is something like this:
char a = '1';...